32 and 2.56 what is the unit rate

Do you need to use fewer centmeters than meters to measure a cabinet

creativ13 [48]

Answer:

No. You need more centimeters because meters are bigger.

Step-by-step explanation:

They're bigger.

Hope this helps!

8 0

2 years ago

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How do you get the same base for the power

rewona [7]

You use division

over 2 or 4 or 3 or 5 or 7 and so on
in this case 2 is good

64 = 2 * 2 * 2 * 2 * 2 * 2 ( use division) = 2^6

16 = 2 * 2 * 2 * 2 = 2^4

number reminder
64 0
32 0
16 0
8 0
4 0
2 0
1 1

so 64 = 2^6 (number of zeros) no reminder

3 0

3 years ago

a wildlife photographer photographs a crocodile and then paddles against a river current for 6 km. Then, hoping to photograph a

rusak2 [61]

Answer:

5 km/h or 6 km/h

Step-by-step explanation:

Let the speed of the boat be x
Speed against the current in the river is x - 2

Time in the river:

6/(x - 2)

Time in the lake:

15/x

The difference:

6/(x - 2) = 15/x - 1

Solve for x to find the speed of the boat

Multiply both sides by x(x - 2) to clear the fraction:

6x = 15(x - 2) - x(x - 2)
6x = 15x - 30 - x² + 2x
x² - 11x + 30 = 0
(x - 5)(x - 6) =0
x -5 = 0, x - 6 = 0
x = 5 km/h, x = 6 km/h

4 0

3 years ago

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Solve for n: n + (-20) = 22 A. 2 B. -42 C. 44 D. None of the above

kifflom [539]

D 44-20=22 so yea i need 20 characters so i’m still typing

8 0

3 years ago

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g Find the equation of the line passing through the point (1, 1, 1) which is perpendicular to the plane containing the points (1

ohaa [14]

Answer:

The equation of the line is given by:

$x = 1 + t$

$y = 1 - 2t$

$z = 1 + t$

Step-by-step explanation:

Parametrizing the equation of the line in function of t, the equation of the line is given by:

$x = x_0 + at$

$y = y_0 + bt$

$z = z_0 + ct$

In which we have an initial point $(x_0,y_0,z_0)$ and $(a,b,c)$ is a vector parallel to the line.

Line passing through the point (1, 1, 1)

This means that $x_0 = y_0 = z_0 = 1$ . So

$x = 1 + at$

$y = 1 + bt$

$z = 1 + ct$

Perpendicular to the plane containing the points (1, 0, 0), (2, 1, 1) and (1, 1, 2).

From this, we get two vectors:

$(2-1,1-0,1-0) = (1,1,1)$

$(1-2,1-1,2-1) = (-1,0,1)$

The parallel vector is given by the determinant of the following matrix:

$\left[\begin{array}{ccc}i&j&k\\1&1&1\\-1&0&1\end{array}\right]$

Which is:

$D = i*1*1 + j*1*-1 + k*1*0 - k*1*(-1) - j*1*1 -i*1*0$

$D = i - j + k - j$

$D = i - 2j + k$

So the vector is (1,-2,1), and the equation of the line is:

$x = 1 + t$

$y = 1 - 2t$

$z = 1 + t$

8 0

2 years ago