Answer:
AC=BD
CAD=CBD
ACB=ADB
Step-by-step explanation:
You're essentially looking for anything of equal proportions. Obviously, your circle is split by several lines, and each side is symmetric. Since you know this, it's simply a matter of identifying one element then finding its symmetric match.
Follow the lines and trace the path with your finger for each question. If you do this, you'll see that AC=BD is an answer that involves a symmetric pair, because these two are equal distances and equal (but opposite) in placement.
Continuing with this method, keep track of the parts of the triangles you trace. With CAD=CBD, you trace across a hypotenuse, a leg, and a base in BOTH, making this true.
Continuing further with ACB=ADB, you trace across a hypotenuse, a leg, and a base with both AGAIN, making this true.
With AB=CD, this is obviously incorrect. You can't jump between points.
Answer:
y= 15
Step-by-step explanation:
Y= Kxz
y=6 x=1/2 z=6
15= K (1/2) (6)
15= K (3)
K= 5
SO
y= (5) (1/2) (6)
Y= 15
Check the picture attached.
Let OB be the radius of circle with center O.
Let B' be the image of B after the described rotation
OB and OB' are sides of the equilateral triangle OBB'.
The x coordinate of B' is the midpoint of OB, that is 5.
In the right triangle B', point (5, 0) and B:
Distance point (5, 0) to B is 5
|B'B|=|OB|=10
so by the pythagorean theorem:

units
Answer: