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qwelly [4]
4 years ago
5

What is the slope of 5x+2y= -8

Mathematics
2 answers:
ivolga24 [154]4 years ago
4 0
M=-5/2 is your answer!
Yuri [45]4 years ago
4 0
To find the slope, get the equation into slope intercept form:

y=mx+b

m stands for slope
b stands for y-intercept

To get your equation like this, subtract 5x from each side.

2y=-8-5x
2y=-5x-8

Finally, divide each side by 2

y=-5/2x-4

Your slope would be -5/2
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mamaluj [8]

Answer:

Step-by-step explanation:

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In one​ lottery, a player wins the jackpot by matching all five numbers drawn from white balls​ (1 through 45​) and matching the
777dan777 [17]

Answer:

39,096,288

Step-by-step explanation:

as we know that

The number of ways to pick 5 numbers from 45  are

45C_5

\frac{45\times44\times43\times42\times41}{5\times4\times3\times2\times1}|

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6 0
4 years ago
1. Which expressions are equivalent to 5^6x5^-3​
Olenka [21]
You just add both of the powers , so 6-3 is 3

the answer is 5^3
7 0
3 years ago
Read 2 more answers
Josie has a small fish tank shaped like a rectangular prism. Her fish tank measures 7 inches tall and 9 inches wide. If Josie's
irinina [24]

Answer:6

Step-by-step explanation:

If we know that the formula of a rectangular prism is length * width * height, and we know the height and width are 7 and 9, the length is the only thing that is left. The volume is 378, and so now we have:

length * 7 * 9 = 378. Dividing the 9 and 7, we get 378/(9*7). The length is 6.

3 0
3 years ago
What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*
pickupchik [31]
<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation x^4-41x^2=-400.

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

x^4-41x^2+400=-400+400.

x^4-41x^2+400=0.

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

x^4-25x^2-16x^2+400=0

Making it into two groups, we get

(x^4-25x^2)+(-16x^2+400)=0

Factoring out GCF of each group, we get

x^2(x^2-25)-16(x^2-25)=0

(x^2-25)(x^2-16) =0

Factoring out  (x^2-25) and (x^2-16) separately by difference of the squares identity a^2-b^2=(a-b)(a+b), we get

(x^2-25) = x^2-5^2= (x-5)(x+5) and

x^2-16 = x^2-4^2 =(x-4)(x+4).

Therefore,

(x-5)(x+5)(x-4)(x+4) =0

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>
6 0
3 years ago
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