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faust18 [17]
2 years ago
5

Soro bought a $50. 00 bus card at the beginning of the week. Each bus ride costs $2. 50. He needs to have at least $20. 00 on hi

s card at the end of this month. To determine how many bus rides he can take between now and the end of this month, Soro wrote and solved the following inequality: 50 minus 2. 5 x greater-than-or-equal-to 20. Negative 2. 5 x greater-than-or-equal-to negative 30. X greater-than-or-equal-to 12. What error, if any, did Soro make when writing or solving this inequality? Soro’s original inequality should have been 50 minus 2. 5 x less-than-or-equal-to 20. Soro should have added 2. 5 to each side for his first step. Soro should have reversed the inequality symbol when using the division property of inequality. Soro’s work shows no errors.
Mathematics
1 answer:
Arisa [49]2 years ago
6 0

The error Soro makes while solving inequality is that "Soro should have reversed the inequality symbol when using the division property of inequality".

<h3>What are inequalities?</h3>

Inequalities help us to compare two unequal expressions. Also, it helps us to compare the non-equal expressions so that an equation can be formed.

It is mostly denoted by the symbol <, >, ≤, and ≥.

The inequality is given as 50-2.5x≥20, now solving the inequality,

50-2.5x \geq 20\\\\\text{Subtract -50 from both the sides}\\\\50-2.5x -50\geq 20-50\\\\-2.5\geq -30

Divide both sides of the inequality by -2.5x, therefore, reverse the inequality symbol when using the division property of inequality.

\dfrac{-2.5x}{-2.5} \leq \dfrac{-30}{-2.5}\\\\x \leq 12

Hence, the error Soro makes when writing or solving inequality 50-2.5x≥20, is that "Soro should have reversed the inequality symbol when using the division property of inequality".

Learn more about Inequality:

brainly.com/question/19491153

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Find the measure of each angle and tell which postulates or theorems you used <br> ?
Illusion [34]

Answer:

∠6=78° ∠7=102° ∠14=78°

Step-by-step explanation:

Angles 6 and 7 are supplementary angles so ∠a+∠b=180°

in this case it would be 102°+x=180° and you subtract 102° from 180° getting 78°

∠7 is the vertical angles postulate stating that any angles vertical to each other are eaqual

7 0
3 years ago
Can someone please help me with question 35?
Genrish500 [490]
First you would find the area of the triangle which would be 84×92 then divide that answer by 2.
Then you will find the area of the circle using the given radius 20.5.
Lets work it out.
84×92=7728
7728÷2=3864 ft²
3864 ft² is the area of the backyard including the pool.
A=pi(20.5)²
A=1320.25 ft²
1320.25 ft² is the area of the pool.
Now we have to subtract to get the area of the backyard without the pool.
3864-1320.25=2543.75 ft²
2543.75 ft² is your answer.
Hope This Helps and God Bless!
8 0
3 years ago
Which formula can be used to find the nth term of a geometric sequence where the fifth term is 1/6 and the common ratio is 1/4?
OlgaM077 [116]

Answer:

a_n = 16(\frac{1}{4})^{n - 1}

Step-by-step explanation:

Given:

Fifth term of a geometric sequence = \frac{1}{16}

Common ratio (r) = ¼

Required:

Formula for the nth term of the geometric sequence

Solution:

Step 1: find the first term of the sequence

Formula for nth term of a geometric sequence = ar^{n - 1}, where:

a = first term

r = common ratio = ¼

Thus, we are given the 5th term to be ¹/16, so n here = 5.

Input all these values into the formula to find a, the first term.

\frac{1}{16} = a*\frac{1}{4}^{5 - 1}

\frac{1}{16} = a*\frac{1}{4}^{4}

\frac{1}{16} = a*\frac{1}{256}

\frac{1}{16} = \frac{a}{256}

Cross multiply

1*256 = a*16

Divide both sides by 16

\frac{256}{16} = \frac{16a}{16}

16 = a

a = 16

Step 2: input the value of a and r to find the nth term formula of the sequence

nth term = ar^{n - 1}

nth term = 16*\frac{1}{4}^{n - 1}

a_n = 16(\frac{1}{4})^{n - 1}

3 0
3 years ago
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
3 years ago
Solve. Will give brain thing
dezoksy [38]

Answer:

Step-by-step explanation:

-1/2 + (3/4 x 4/9)

-1/2 + (3/9)

= - 1/2 + (1/3)

= - 1/6

8 0
3 years ago
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