Identify the parts of the wave.

HELPPP<br>yall please help my sister won't help me

ira [324]

$\text{H}_3\text{PO}_4 + 3\text{KOH} \longrightarrow \text{K}_3 \text{PO}_4 +3\text{H}_2 \text{O}\\\\10\text{Na} +2 \text{NaNO}_3 \longrightarrow 6\text{Na}_2 \text{O} + \text{N}_2\\\\\ 2\text{H}_3 \text{PO}_4 + 3\text{Mg(OH)}_2 \longrightarrow \text{Mg}_3(\text{PO}_4)_2+6\text{H}_2 \text{O}\\\\2\text{Al(OH)}_3 + 3\text{H}_2 \text{CO}_3 \longrightarrow \text{Al}_2(\text{CO}_3)_3 + 6\text{H}_2 \text{O} \\\\2\text{C}_6\text{H}_6+15\text{O}_2 \longrightarrow 12\text{CO}_2 +6\text{H}_2 \text{O}\\$

$\text{Pb(OH)}_2 +2\text{HCl} \longrightarrow \text{PbCl}_2 +2 \text{H}_2 \text{O}$

$2\text{Mn} + 6\text{HI} \longrightarrow 3 \text{H}_2+2\text{MnI}_3$

3 0

3 years ago

Calculate the mass of 12.3 moles of MgSO4.

Afina-wow [57]

Answer:

614 034 kg

Explanation:

n = m/Mm

m = n * Mm

Mm(MgSO4) = 1 * 24.3 * 1 * 32.1 * 4 * 16 = 49921.92

m = 12.3 * 49921.92

m = 614 034 kg

8 0

3 years ago

Read 2 more answers

5. A 25 ml graduated cylinder has a volume of water of 10 ml, when a glass marble is place in the

IceJOKER [234]

Answer:

The volume of the marble is 10 mL.

Explanation:

From the question given above, the following data were obtained:

Volume of water = 10 mL

Rise in water = 10 mL

Volume of marble =.?

From the question given above, the water level rise by 10 mL when a glass marble was placed into the water.

This is equally the volume of the marble as the marble will displace it's volume when placed in the water according to Archimedes' principle.

Therefore,

Rise in water = 10 mL = volume of marble.

4 0

3 years ago

A water bottling company is looking to achieve maximum production from the following reversible reaction. If the reaction has re

dybincka [34]

Answer:

Remove the already produced water and allow the reaction to reach equilibrium again.

Explanation:

<em>According to Le Chatelier principle, when a reaction is in equilibrium and one of the factors that influence the rate of reaction is altered, the equilibrium will shift so as to annul the effects of the change.</em>

If the product is continuously being removed from a reaction that is in equilibrium, more product will continued to be formed in another to annul the effect of reduction in the concentration of product.

Hence, in order to maximize production of water in the reaction, the product (water) needs to be removed and the reaction allowed to reach equilibrium again.

7 0

4 years ago

Volume of 0.150 M NaOH solution required to neutralize 25mL of a 0.055 M HCl solution?

Inessa05 [86]

<h3>Answer:</h3>

9.17 mL

<h3>Explanation:</h3>

In this question<u> we are given;</u>

Molarity of NaOH as 0.150 M
Molarity of the acid, HCl as 0.055 M
Volume of the acid, HCl as 25 mL
Equation for the reaction as;

NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq)

We are required to determine the volume of the alkali, NaOH used;

<h3>Step 1: Determine the moles of the acid, HCl</h3>

Molarity = Number of moles ÷ Volume

Thus, rearranging the formula;

Moles = Molarity × volume

= 0.055 M × 0.025 L

= 0.001375 moles

<h3>Step 2: Moles of the alkali, NaOH</h3>

From the reaction; 1 mole of HCl reacts with 1 mole of NaOH

Therefore;

Moles of HCl = Moles of NaOH

Hence; Moles of NaOH = 0.001375 moles

<h3>Step 3: Determine the volume of the alkali, NaOH</h3>

From the previous equation;

Molarity = Moles ÷ Volume

Rearranging the equation;

Volume = Moles ÷ Molarity

Therefore;

Volume of NaOH = 0.001375 moles ÷ 0.150 M

= 0.00917 L, but, 1 L = 1000 mL

= 9.17 mL

Therefore, the volume of NaOH required is 9.17 mL

5 0

4 years ago