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Vera_Pavlovna [14]
3 years ago
11

The solid in question 2 was aluminum sulfate, al2(so4)3. calculate the molar heat of solution, δhsoln, for aluminum sulfate. hin

t: the units for molar heat of solution are kilojoules per mole (kj/mole). first determine the heat released per gram of solid.
Chemistry
1 answer:
Sidana [21]3 years ago
6 0

The solution for this problem is:

The information given lacks but nevertheless the answer is:
So, the total heat free by dissolving the solute was 1386 + 32 = 1417 J
Then, dissolving of the solute will have released -1417 J. So, per gram of Al2 (SO4)3 dissolved: 
-1417 J / 25 g = -56.7 J/g 


Translating that to a per mole: -56.7 J/g X 342 g/mol = -1.94X10^4 J/mol = -19 kJ/mol = this would be Delta Hsoln

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The oxidation of copper(I) oxide, Cu2O(s) , to copper(II) oxide, CuO(s) , is an exothermic process. 2Cu2O(s)+O2(g)⟶4CuO(s) The c
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The work is  

      W = -0.369kJ

The energy  change of the reaction is  \Delta U _{rxn} = 43.839 kJ  

Explanation:

From the question we are told that

    The chemical equation for this reaction is

             2 Cu_2 O + O_2_{(g)} ----> 4 CuO_{(s)}

     The mass of  Cu_2 O is  m = 42.60g

      The enthalpy Cu_2 O is  \Delta H_{re} = -43.47 \ kJ this also the change in energy in terms of heat

      The pressure at which it is oxidized is P = 1\  bar

The  no of moles of Cu_2 Oused in this reaction is mathematically represented as

        n = \frac{mass \ of   \ Cu_2 O}{Molar \ mass \  of   \ Cu_2 O}

The molar mass of Cu_2 O is  a constant with a value  M = 143.1 g/mol

   Now substituting values

             n = \frac{ 42.60}{143.1}

            n = 0.29769 \ moles

From the reaction we see that

Two mole of Cu_2 O  reacts with One mole of O_2 to give Four moles of  CuO_{(s)}

This means that

One mole of  Cu_2 O  reacts with 0.5 mole of O_2 to give two moles of  CuO_{(s)}

it also implies that

0.29769 \ mole of  Cu_2 O  reacts with 0.5 * 0.29769 moles of O_2 to give 2* 0.29769 moles of  CuO_{(s)}

so

0.29769 \ mole of  Cu_2 O  reacts with 0.149 moles of O_2 to give 0.595 moles of  CuO_{(s)}

Now the number of moles of gaseous reactant is

      N_{O_2} = 0.149 \ moles

The number of moles of gaseous product  is

     N_p = 0 \ moles

So the change in number of moles for gaseous  compounds is mathematically evaluated as

         \Delta N = 0- 0.149 \ moles

        \Delta N = - 0.149 \ moles

Now the workdone for  the compound Cu_2 O is mathematically represented as

        W = \Delta N RT

Where R is the gas constant with a value of R = 8.314 J/mol \cdot K

            T is the temperature with a value  T = 25 + 273 = 298 K

     Substituting values

     W = -0.149 * 8.314 * (298)

     W = -0.369kJ

Generally the internal energy change of the reaction can be represented as

           \Delta U _{rxn} = \Delta H_{re} - W

Substituting value

        \Delta U _{rxn} = -43.47 -  (-0.369)

        \Delta U _{rxn} = 43.839 kJ  

This is the internal energy change on the reaction for 42.60 g of Cu_2 O

       

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