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Vera_Pavlovna [14]
3 years ago
11

The solid in question 2 was aluminum sulfate, al2(so4)3. calculate the molar heat of solution, δhsoln, for aluminum sulfate. hin

t: the units for molar heat of solution are kilojoules per mole (kj/mole). first determine the heat released per gram of solid.
Chemistry
1 answer:
Sidana [21]3 years ago
6 0

The solution for this problem is:

The information given lacks but nevertheless the answer is:
So, the total heat free by dissolving the solute was 1386 + 32 = 1417 J
Then, dissolving of the solute will have released -1417 J. So, per gram of Al2 (SO4)3 dissolved: 
-1417 J / 25 g = -56.7 J/g 


Translating that to a per mole: -56.7 J/g X 342 g/mol = -1.94X10^4 J/mol = -19 kJ/mol = this would be Delta Hsoln

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The problem is incomplete. However, there can only be two probable questions for this problem. First, you can be asked the individual partial pressures of each gas. Second, you can be asked the volume occupied by each gas. I can answer both cases for you.

1.

Let's assume ideal gas.
Pressure for N₂: 2 bar*0.4 = 0.8 bar
Pressure for CO₂: 2 bar*0.5 = 1 bar
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3 0
3 years ago
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Answer:

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Explanation:

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