A. I’m not positive but I’m pretty sure
Answer:
low
Explanation:
We were informed in the question that the student had incorrectly recorded the mass of cup + sample as 2.20 g but inadvertently used 2.00 g in the calculations.
This error will cause a slight decrease in the mass of water and ultimately decrease the number of moles of water in the hydrate.
What i am saying is that the number of moles of water obtained in the calculation will be artificially low.
Answer:
156 g
Explanation:
Let's consider the following reaction.
2 NaN₃(s) → 2 Na(s) + 3 N₂
(g)
We can find the moles of N₂ using the ideal gas equation.
P × V = n × R × T
1.50 atm × 60.0 L = n × (0.08206 atm.L/mol.K) × 305 K
n = 3.60 mol
The molar ratio of N₂ to NaN₃ is 3:2. The moles of NaN₃ are:
3.60 mol N₂ × (2 mol NaN₃ / 3 mol N₂) = 2.40 mol NaN₃
The molar mass of NaN₃ is 65.01 g/mol. The mass of NaN₃ is:
2.40 mol × 65.01 g/mol = 156 g
Answer:
Explanation:
Hello,
In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:
We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:
Thus, solving for the yielded volume of carbon dioxide we obtain:
Best regards.
Answer:
boring
Explanation:
life would be meaningless like everyone being like on person
