<u>Answer:</u> The rate law for the reaction is ![\text{Rate}=k'[H+][H_2O_2][Br^-]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%27%5BH%2B%5D%5BH_2O_2%5D%5BBr%5E-%5D)
<u>Explanation:</u>
Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.
In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.
The chemical equation for the oxidation of bromide ions by hydrogen peroxide in aqueous acid solution follows:
The intermediate reaction of the mechanism follows:
<u>Step 1:</u> 
<u>Step 2:</u> 
<u>Step 3:</u> 
As, step 2 is the slow step. It is the rate determining step
Rate law for the reaction follows:
![\text{Rate}=k[H_3O_2^+][Br^-]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BH_3O_2%5E%2B%5D%5BBr%5E-%5D)
......(1)
As, ![[H_3O_2^+]](https://tex.z-dn.net/?f=%5BH_3O_2%5E%2B%5D)
is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.
Applying steady state approximation for from step 1, we get:
![K=\frac{[H_3O_2^+]}{[H^+][H_2O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BH_3O_2%5E%2B%5D%7D%7B%5BH%5E%2B%5D%5BH_2O_2%5D%7D)
![[H_3O_2^+]=K[H^+][H_2O_2]](https://tex.z-dn.net/?f=%5BH_3O_2%5E%2B%5D%3DK%5BH%5E%2B%5D%5BH_2O_2%5D)
Putting the value of in equation 1, we get:
![\text{Rate}=k.K[H^+][H_2O_2][Br^-]\\\\\text{Rate}=k'[H+][H_2O_2][Br^-]](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk.K%5BH%5E%2B%5D%5BH_2O_2%5D%5BBr%5E-%5D%5C%5C%5C%5C%5Ctext%7BRate%7D%3Dk%27%5BH%2B%5D%5BH_2O_2%5D%5BBr%5E-%5D)
Hence, the rate law for the reaction is
Answer:
The atoms in the first period have electrons in 1 energy level. The atoms in the second period have electrons in 2 energy levels. The atoms in the third period have electrons in 3 energy levels. The atoms in the fourth period have electrons in 4 energy levels.
Answer:
See Explanation
Explanation:
Mathematically, this means to combine like terms, such as terms with the same variable. In chemistry, this can refer to polar objects combining with polar objects while nonpolar objects combine with nonpolar objects.
Answer:
(NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→ AlPO₄(l) + 3NH₄NO₃(l)
Explanation:
Data Give:
Reaction between ammonium phosphate solution and solution of aluminum nitrate
- Write a balanced chemical equation
Details:
To write a balanced chemical equation we have to know formula units of compounds or molecules
Formula units
ammonium phosphate : (NH₄)₃PO₄
aluminum nitrate: Al(NO₃)₃
ammonium nitrate: NH₄NO₃
Now to write a chemical equation
- we have to write the chemical formulas or formula unit of each compound
- write the reactant on left side of the arrow
- write the product on the right side of the arrow
- put a plus sign in 2 reactants and products on each side of the arrow
- balance the equation by putting coefficient with compound formula
- write the phase symbols on the right corner of the compound formula in brackets
So the Reaction will be
(NH₄)₃PO₄ + Al(NO₃)₃ -----------→ AlPO₄ + NH₄NO₃
Now balance the Chemical equation
(NH₄)₃PO₄ + Al(NO₃)₃ -----------→ AlPO₄ + 3NH₄NO₃
Now write the phase Symbols
(NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→ AlPO₄(l) + 3NH₄NO₃(l)
all compounds in the reaction are in liquid form and soluble in water
*** Note:
There is no aluminum nitrite in chemicals formulas
Also ammonium nitrite can not be used in pure isolated form due to its highly instability
ans A. 13 to 3
solution:
Total puppies for sale=6
Total puppies left = 2
hence total puppies sold= 6 - 2 = 4
cost of a puppy= $ 104
so cost of 2 puppies = 104 x 4
=416$
Now for kittens:
Total kittens for sale = 12
Total kittens left = 8
hence total kittens sold=12 - 8 =4
cost of a kitten = $24
so cost of 4 kittens= 24x 4=96$
Now ratio of sales of puppies to kittens = 208$/96$
= 13/3 or 13:3 or 13 to 3
I hope this explanation will help you to understand this problem
