Answer:Jarvis's class average is 75
Step-by-step explanation:
The total possible average score for the math course is 100
a) If the teacher rates homework at 10%, it means that the total possible score for homework
is 10/100 × 100 = 10
If his homework average is 93, then his score would be
(93×10)/100 = 9.3
b) If the teacher rates quizzes at 30%, it means that the total possible score for quizzes
is 30/100 × 100 = 30
If his quiz average is 82, then his score would be
(82×30)/100 = 24.6
c) If the teacher rates test at 40%, it means that the total possible score for quizzes
is 40/100 × 100 = 40
If his quiz average is 72, then his score would be
(72×40)/100 = 28.8
d) If the teacher rates final exam at 20%, it means that the total possible score for quizzes
is 20/100 × 100 = 20
If his final exam is 60, then his score would be
(60×20)/100 = 12
Jarvis's class average would be
9.3 + 24.6 + 28.8 + 12 = 74.7
Approximately 75
Answer: He played a total of 104 chess games.
Step-by-step explanation:
9:4
72:x
9:4 = 72:x
72 * 4 = 288
288/9 = 32
x = 32
32 + 72 = 104
2/2, 4/4, 5/5, 7/7, or any fraction with the same numerator and denominator will be equivalent. All fractions equal 1.
Answer:
The median is 26
Step-by-step explanation:
A "median" is equivalent to when the terms are arranged in the proper order, whichever term is in the "middle".
So- first, arrange the terms in ascending order.
[22, 22, 23, 23, 29, 29, 29, 31]
There are an even number- eight- terms in total, so we will take the average of the two "middle" terms.
(29+23)/2; 29 and 23 are the "middle" terms, and there are two of them.
(52)/2 = 26
Therefore, the median is 26.
I hope this helped! :)
1)
f(x)=tan 90º=indeterminated or ∞
Answer: y-value=indeterminated or ∞.
2)
Law of sines:
a/sin A=b/ sinB
In this case:
24 /sin 92º=7/sin Z
sin Z=(7*sin 92º)/24=0.29148...≈0.29
Z=arc sin (0.29)=16.95º
Answer: Z=16.95º.
3)
Law of cousines:
a²=b²+c²-2bc(cos A)
In this case:
12²=22²+19²-2(22)(19)cos T
144=484+361-836 cos T
-836 cos T=144-484-361
-836 cos T=-701
cos T=-701/-836
cos T=0.83851...≈0.84
T=arc cos (0.84)=33.02
Answer: T=33.02º
4)
The hypotenuse would be EF, because it is in front of the right angle.
The legs would be EG and FG
Answer: The legs would be EG and FG.
5)
cot Ф= adjacent /opposite=10/24=5/12
Answer: cot Ф=5/12
