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Allushta [10]
3 years ago
6

Physical properties such as melting point, boiling point, and solubility are all dependent on the type of interparticle forces a

substance experiences. Identify the type of interparticle force that has the greatest influence on the physical properties for each substance.
Chemistry
1 answer:
RoseWind [281]3 years ago
5 0

Answer:

CaCl2 and KI- ionic

PCl3 and CH4-dispersion forces

NH2OH- hydrogen bonding

Explanation:

Complete question

Physical properties such as melting point, boiling point, and solubility are all dependent on the type of interparticle forces a substance experiences. Identify the type of interparticle force that has the greatest influence on the physical properties for each substance. Cl2, NH2OH, PCl3, CH4, CaCl2, KI

Solution

Calcium and Potassium are metal and they form ionic bonds with the non metal such as CaCl2 and KI

PCl3 and CH4- have dispersion forces as their structural arrangement distribute electrons around any atom and molecule.

NH2OH- hydrogen bonding - Due to the presence of H and O atoms, there exists hydrogen bond with in this molecule.

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Consider the following balanced equation:3Ca(NO3)2(aq) + 2Na3PO4(aq) → Ca3(PO4)2(s) + 6NaNO3(aq)If 24.2 moles of Na3PO4(aq) reac
Tomtit [17]

Answer:

69.7% is percent yield

Explanation:

Based on the reaction:

3Ca(NO3)2(aq) + 2Na3PO4(aq) → Ca3(PO4)2(s) + 6NaNO3(aq)

2 moles of Na3PO4 react producing 6 moles of NaNO3.

As 24.2 moles of Na3PO4 react, theoretical moles of NaNO3 produced are:

24.2 moles Na3PO4 * (6 moles NaNO3 / 2 moles Na3PO4) =

72.6 moles of NaNO3

As there are produced 50.6 moles of NaNO3, percent yield is:

50.6 moles NaNO3 / 72.6 moles NaNO3 =

<h3>69.7% is percent yield</h3>
7 0
3 years ago
The equilibrium constant Kc for the reaction PCl3(g) + Cl2(g) ⇌ PCl5(g) is 49 at 230°C. If 0.70 mol of PCl3 is added to 0.70 mol
Ymorist [56]

Answer : The correct option is, (B) 0.11 M

Solution :

First we have to calculate the concentration PCl_3 and Cl_2.

\text{Concentration of }PCl_3=\frac{\text{Moles of }PCl_3}{\text{Volume of solution}}

\text{Concentration of }PCl_3=\frac{0.70moles}{1.0L}=0.70M

\text{Concentration of }Cl_2=\frac{\text{Moles of }Cl_2}{\text{Volume of solution}}

\text{Concentration of }Cl_2=\frac{0.70moles}{1.0L}=0.70M

The given equilibrium reaction is,

                            PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

Initially                 0.70        0.70              0

At equilibrium    (0.70-x)   (0.70-x)           x

The expression of K_c will be,

K_c=\frac{[PCl_5]}{[PCl_3][Cl_2]}

K_c=\frac{(x)}{(0.70-x)\times (0.70-x)}

Now put all the given values in the above expression, we get:

49=\frac{(x)}{(0.70-x)\times (0.70-x)}

By solving the term x, we get

x=0.59\text{ and }0.83

From the values of 'x' we conclude that, x = 0.83 can not more than initial concentration. So, the value of 'x' which is equal to 0.83 is not consider.

Thus, the concentration of PCl_3 at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of Cl_2 at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M

The concentration of PCl_5 at equilibrium = x = 0.59 M

Therefore, the concentration of PCl_3 at equilibrium is 0.11 M

3 0
4 years ago
Glycerol is a subunit molecule of a
Schach [20]
<span>Glycerol is a sub-unit molecule of a Lipid

So, option C is your answer.

Hope this helps!
</span>
6 0
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marusya05 [52]

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Hope it helps you.

5 0
3 years ago
According to the reaction below, what mass of oxygen gas is required to produce 22 g of carbon dioxide?
alisha [4.7K]
The answer is B)4.0g
6 0
4 years ago
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