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kvasek [131]
1 year ago
14

For what order reaction does the half-life get longer as the initial concentration increases?

Chemistry
1 answer:
nasty-shy [4]1 year ago
3 0

The half-life gets longer as the initial concentration increases in zero-order reaction.

The amount of time it takes for the concentration of a given reactant to reach 50% of its initial concentration is known as the half-life of a chemical reaction (i.e. the time taken for the reactant concentration to reach half of its initial value).

For zero order reaction:

The half-life is given as:

t_{1/2}=\frac{[A]_{0}}{2k} where k is the rate constant of the reaction and [A]_{0} is the initial concentration.

As we can see that the half-life is directly proportional to the initial concentration. Therefore, when the initial concentration increases the half-life gets longer.

For the first-order reaction,

The half-life is given as:

t_{1/2}=\frac{\ln 2}{k}=\frac{0.693}{k}

A first-order reaction's half-life is independent of the initial concentration.

For a second-order reaction,

The half-life is:

t_{\frac{1}{2} }=\frac{1}{k[A]_{0}}

The initial concentration is inversely proportional to the half-life, so when the initial concentration increases the half-life will get shorter.

Learn more about half life here:

brainly.com/question/1160651

#SPJ4

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Tetrahydrofuran (THF) is a common organic solvent with a boiling point of 339 K. Calculate the total energy (q) required to conv
poizon [28]

Explanation:

For the given reaction, the temperature of liquid will rise from 298 K to 339 K. Hence, heat energy required will be calculated as follows.

             Q_{1} = mC_{1} \Delta T_{1}

Putting the given values into the above equation as follows.

           Q_{1} = mC_{1} \Delta T_{1}

                      = 27.3 g \times 1.70 J/g K \times 41

                      = 1902.81 J

Now, conversion of liquid to vapor at the boiling point (339 K) is calculated as follows.

           Q_{2} = energy required = mL_{v}

    L_{v} = latent heat of vaporization

Therefor, calculate the value of energy required as follows.

             Q_{2} = mL_{v}

                         = 27.3 \times 444

                         = 12121.2 J

Therefore, rise in temperature of vapor from 339 K to 373 K is calculated as follows.

            Q_{3} = mC_{2} \Delta T_{2}

Value of C_{2} = 1.06 J/g,    \Delta T_{2} = (373 -339) K = 34 K

Hence, putting the given values into the above formula as follows.

             Q_{3} = mC_{2} \Delta T_{2}

                       = 27.3 g \times 1.06 J/g \times 34 K

                       = 983.892 J

Therefore, net heat required will be calculated as follows.

            Q = Q_{1} + Q_{2} + Q_{3}

                = 1902.81 J + 12121.2 J + 983.892 J

                = 15007.902 J

Thus, we can conclude that total energy (q) required to convert 27.3 g of THF at 298 K to a vapor at 373 K is 15007.902 J.

5 0
3 years ago
Four moles of Argon gas are at a pressure of 1.90 atm, and the temperature is 50 degrees C. What is the volume of the gas?
soldier1979 [14.2K]
N = 4 moles of Ar2, P = 1.90 atm, V = ?
T = 50C = 273 + 50K = 323K
PV = nRT --> V = nRT/P
V = (4)(.0821)(323)/1.90
V = 106.07/ 1.9
V = 55.8 L
4 0
3 years ago
When C2H4(g) reacts with H2O(g) to form CH3CH2OH(g) according to the following equation, energy is released into the surrounding
kirill [66]

Answer:

Exothermic

General Formulas and Concepts:

<u>Chemistry</u>

<u>Thermodynamics</u>

  • Exothermic - releases heat as a product
  • Endothermic - absorbs heat as a reactant

Explanation:

We are given that the reaction takes place between C₂H₄ (g) and H₂O (g) to form CH₃CH₂OH (g) and is <em>releasing heat</em>.

This means that heat would be product as it is being released during the reaction.

Therefore, we have an exothermic reaction.

3 0
3 years ago
How many moles of oxygen are needed to react with 7.5 moles of aluminum?
LuckyWell [14K]
Equation for oxygen gas molecules
1.5O₂ + 2Al => Al₂O₃
ratio of aluminium to oxygen is
2:1.5
when Al is 7.5
O₂ is 3.75
4 0
4 years ago
Please Help Me!
S_A_V [24]

Answer:

The answer to your question is      SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

Explanation:

Reaction

                                SO₂   +   H₂    ⇒     H₂S   +  H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                    1

                               2                  Hydrogen               4

                              2                   Oxygen                   1

This reaction is unbalanced so we need to balance it.

                              SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                   1

                              6                  Hydrogen               6

                              2                   Oxygen                  2

Now, the reaction is balanced

3 0
4 years ago
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