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kvasek [131]
1 year ago
14

For what order reaction does the half-life get longer as the initial concentration increases?

Chemistry
1 answer:
nasty-shy [4]1 year ago
3 0

The half-life gets longer as the initial concentration increases in zero-order reaction.

The amount of time it takes for the concentration of a given reactant to reach 50% of its initial concentration is known as the half-life of a chemical reaction (i.e. the time taken for the reactant concentration to reach half of its initial value).

For zero order reaction:

The half-life is given as:

t_{1/2}=\frac{[A]_{0}}{2k} where k is the rate constant of the reaction and [A]_{0} is the initial concentration.

As we can see that the half-life is directly proportional to the initial concentration. Therefore, when the initial concentration increases the half-life gets longer.

For the first-order reaction,

The half-life is given as:

t_{1/2}=\frac{\ln 2}{k}=\frac{0.693}{k}

A first-order reaction's half-life is independent of the initial concentration.

For a second-order reaction,

The half-life is:

t_{\frac{1}{2} }=\frac{1}{k[A]_{0}}

The initial concentration is inversely proportional to the half-life, so when the initial concentration increases the half-life will get shorter.

Learn more about half life here:

brainly.com/question/1160651

#SPJ4

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How many grams of KCl is needed to make .75 L of a 1 M solution of KCl?
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Answer:

The answer to your question is 25.9 g of KCl

Explanation:

Data

Grams of KCl = ?

Volume = 0.75 l

Molarity = 1 M

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

Number of moles = Molarity x volume

Substitution

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Simplification

Number of moles = 0.75 moles

Molecular mass KCl = 39 + 35.5 = 34.5

Use proportions to find the grams of KCl

                          34.5 g of KCl ----------------  1 mol

                             x                  ----------------  0.75 moles

                            x = (0.75 x 34.5) / 1

                            x = 25.9 g of KCl

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