This may seem confusing because they give you two masses, but all you have to do is pick one to do the calculations. Personally, I would pick O2, since the molar mass is easier to calculate. The answer would be 3.3 g (rounded for sig figs). To get this, first take the 5.9 grams of O2 and convert it to moles by dividing by the molar mass of oxygen gas, which is 32. Then, multiply both by the mole-mole ratio, which is 2:2, or simply 1:1. After that, multiply that by 18g, which is the molar mass of water to get grams of water.
REMEMBER, you have to write and balance the chemical equation before you can do any of that work.
That happens to be CH4 + 2O2 => CO2 + 2H2O
The correct answer for the question that is being presented above is this one: "The pH of the solution containing NaF and HF would be lower than that of a solution of HF only.; <span>THe pH of the solution containing NaF and HF would be higher than that of a solution of HF only."</span>
The pH of the solution is 4.38.
<h3>What is the pH?</h3>
The first thing that we must do is to set up the ICE table for the reaction as shown;
Given that;
HA = 1.8 M
HA(aq) + H2O(l) ⇔ H3O^+(aq) + A^-(aq)
I 1.8 0 0
C - x +x +x
E 1.8 - x x x
K = [H3O^+] [A^-]/[HA]
9.55 × 10^−10 = x^2/0.0158 - x
9.55 × 10^−10(1.8 - x ) = x^2
1.719 * 10^-9 - 9.55 * 10^-10x = x^2
x^2 + 9.55 * 10^-10x - 1.719 * 10^-9 = 0
x=0.000041 M
pH = -log(0.000041 M)
pH = 4.38
Learn more about pH:brainly.com/question/15289741
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The meaning of the atomic radius is a large portion of the normal internuclear separation of an atom. It isn't conceivable to deal with one atom. In any case, here internuclear remove does not mean measurement of a solitary particle but rather it implies the separation between the core of two atoms of a similar component.
Answer:
Do a quick conversion: 1 moles Ca(ClO3)2 = 206.9804 gram using the molecular weight calculator and the molar mass of Ca(ClO3)2. ... How many moles Ca(ClO3 )2 in 1 grams? ... of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.
Explanation:
(jayaanilanmol's answer)
