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krek1111 [17]
3 years ago
15

1. we used __________ to represent an element.

Chemistry
2 answers:
Ludmilka [50]3 years ago
8 0

Answer:

1. we used <u>chemical</u><u> </u><u>formula</u> to represent an element.

choice a. is correct

2. the chemical formula of a molecule shows the <u>number and kind of atoms contained in the molecule</u>.

choice c. is correct

3. which of the following is an atom?

= K [Potassium]

choice a. is correct

4. which of the following is a molecule?

= CO [Carbon Monoxide]

choice d. is correct

scoundrel [369]3 years ago
6 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

1. we used <u>Symbol</u> to represent an element.

2. The chemical formula of a molecule shows the <u>number and kind of atoms contained in the molecule</u>.

3. K (potassium) is the atom among the given choices.

4. CO (carbon - monoxide) is the molecule among given choices.

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Given the balanced equation representing a reaction:
zhenek [66]
The answer is (3). The powdered iron and the piece iron is the same substance and is just different in the shape. So the reason is the power has larger surface area for reaction occurs.
5 0
3 years ago
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The vapor pressure of substance X is 100. mm Hg at 1080.°C. The vapor pressure of substance X increases to 600. mm Hg at 1220.°C
artcher [175]

Explanation:

The given data is as follows.

         P_{1} = 100 mm Hg or \frac{100}{760}atm = 0.13157 atm

         T_{1} = 1080 ^{o}C = (1080 + 273) K = 1357 K

         T_{2} = 1220 ^{o}C = (1220 + 273) K = 1493 K

         P_{2} = 600 mm Hg or \frac{600}{760}atm = 0.7895 atm

          R = 8.314 J/K mol

According to Clasius-Clapeyron equation,

                   log(\frac{P_{2}}{P_{1}}) = \frac{\Delta H_{vap}}{2.303R}[\frac{1}{T_{1}} - \frac{1}{T_{2}}

            log(\frac{0.7895}{0.13157}) = \frac{\Delta H_{vap}}{2.303 \times 8.314 J/mol K}[\frac{1}{1357 K} - \frac{1}{1493 K}]

          log (6) = \frac{\Delta H_{vap}}{19.147}[\frac{(1493 - 1357) K}{1493 K \times 1357 K}]

                0.77815 = \frac{\Delta H_{vap}}{19.147J/K mol} \times 6.713 \times 10^{-5} K

              \Delta H_{vap} = 2.219 \times 10^{5} J/mol

                                   = 2.219 \times 10^{5}J/mol \times 10^{-3}\frac{kJ}{1 J}

                                    = 221.9 kJ/mol

Thus, we can conclude that molar heat of vaporization of substance X is 221.9 kJ/mol.

4 0
3 years ago
What is the mass of HF produced by three reaction of 3.0 10 to the 23 molecules of H2 with excess F2
JulijaS [17]

Answer:

It is 20. g HF

Explanation:

H2 + F2 ==> 2HF  ...  balanced equation

Since the question is asking us to find the mass of product formed, we will want to first convert the molecules of H2 into moles of H2 (we could do this at the end of the calculations, but it's just as easy to do it now).

moles of H2 present (using Avogadro's number):  

3.0x1023 molecules H2 x 1 mole H2/6.02x1023 molecules = 0.498 moles H2

From the balanced equation, we see that 1 mole H2 produces 2 moles HF.  Therefore, we can now find the theoretical mass of HF produced from 0.498 moles H2:

0.498 moles H2 x 2 moles HF/1 mol H2 = 0.996 moles HF formed.

The molar mass of HF = 20.01 g/mole, thus...

0.996 moles HF x 20.01 g/mole = 19.93 g HF = 20. g HF formed (to 2 significant figures)

6 0
3 years ago
Valence electrons<br> Fill in the blanks
IgorC [24]

Answer:

Valence electrons or outer electrons are most important as they participate in bonding. The octet rule states that atoms gain, lose, or share valence electrons to have filled energy levels.. this gives atoms a stable configuration like that of the nearest noble gas.

6 0
3 years ago
Why is ethanol a member of the homologous series of alcohols but propane is not<br> I’m in the exam!
Mumz [18]

Answer:

I hope it helps..... you can stop at the full-stop

3 0
3 years ago
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