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2 years ago

Goodmorning all help me guys

Mathematics

1 answer:

kotegsom [21]2 years ago

8 0

Answer:

Step-by-step explanation:

1) Distance covered by motorcycle = x

y = 50 + (x -2)*10

2)Distance traveled = 5 km

y = 50 + ( 5-2) *10

= 50 + 3*10

= 50 + 30

= 80

Seth will be paid Php 80

3) y = 120

50 + (x - 2)* 10 = y

50 + (x -2) *10 = 120

50 + 10x - 2*10 = 120

50 + 10x - 20 = 120

30 + 10x = 120

10x = 120 - 30

10x = 90

x = 90/10

x = 9

A passenger can travel 9 km.

4)y = (x - 2)*10

y = 10x - 20

20 + y = 10x

20 = 10x - y

10x - y = 20 {Ax + By = C form}

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Nick can run the 440 yard dash in 55 seconds, and Jack can run it in 88 seconds. How great a handicap must Nick give Jack for th

Zepler [3.9K]

Jack --> 440 = rate * 88Jack --> 5 yrds/sex = rateJack in 55 seconds --> distance = 5 * 55 = 275 yrds440 - 275 = 165 yards handicap.

8 0

3 years ago

Willie and anjali each improved their yards by planting daylilies and ivy. They bought their supplies from the same store. Willi

Fiesta28 [93]

Answer:the cost of one day lily = $9 and cost of one pot of ivy = $2

Step-by-step explanation:

Step 1

let day lilies be rep as d

and ivy be represented as i

So that The expression for what Willie spent on 12 day lilies and 4 pots of ivy = $116 be

12 d+ 4i = 116 ---- equation 1

and for Anjali spending $60 on 6 day lilies and 3 pots of ivy be

6d+ 3i = $60------ equation 2

Step 2 --- Solving

12 d+ 4i = 116 ---- equation 1

6d+ 3i = $60------ equation 2

Multiply equation 2 by (2) and subtracting equation 1 from it

12d+ 6i= 120

--12 d+ 4i = 116

2 i= 4

i = 4/2 = 2

TO find d, putting the value of i = 2 in equation 1 and solving

12d+ 4(2) = 116

12d= 116-8

12d= 108

d= 108/12= 9

Therefore the cost of one day lily = $9 and cost of one pot of ivy = $2

5 0

2 years ago

Can someone help me !

rosijanka [135]

Answer:

Step-by-step explanation:

It's the only one with an addition sign...... seems logical, let me know if you got it correct

7 0

3 years ago

GEOMETRY PROOFS!

yarga [219]

From the given figure ,

RECA is a quadrilateral

RC divides it into two parts

From the triangles , ∆REC and ∆RAC

RE = RA (Given)

angle CRE = angle CRA (Given)

RC = RC (Common side)

Therefore, ∆REC is Congruent to ∆RAC

∆REC =~ ∆RAC by SAS Property

⇛CE = CA (Congruent parts in a congruent triangles)

Hence , Proved

Additional comment:-

SAS property:-

"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)

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