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Liula [17]
2 years ago
13

What is the solution to this system of linear equations?

Mathematics
1 answer:
galben [10]2 years ago
7 0

Answer:

(6, 2)

Step-by-step explanation:

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As seen in the diagram below, Hawa is building a walkway with a width of a feet to go
slega [8]

Answer:

8 feet

Step-by-step explanation:

you have to calculate :(19+2x)(6+2x)=770

you will get X1=8,X2= negetive some value but measurement cant be negative .if you put X=8 you'll find LHS=RHS

7 0
2 years ago
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Find the equation of a line that contains the points (-8, 7) and (-8, -2). Please help!!!
FrozenT [24]

Answer:

x = -8

Step-by-step explanation:

(-8, 7) and (-8, -2)

m=(y2-y1)/(x2-x1)

m=(-2-7)/(-8+8)

m=(-9)/0

m = undefined slope or no slope

x = -8

4 0
2 years ago
How
Lady_Fox [76]
Your mom is 65. uh huh
4 0
2 years ago
What is the solution to 34x + 95 = 3 (14X +9)
Leya [2.2K]
X=17/2
Decimal form : x=8.5
8 0
3 years ago
Read 2 more answers
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
2 years ago
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