3 years ago

Anybody Know This. ?

Mathematics

1 answer:

PolarNik [594]3 years ago

5 0

Answer:

3-Equalateral

Step-by-step explanation:

All the sides are all equal, which basically eliminates isosceles, isosceles acute, and scalene, therefore the answer is Equalateral.

You might be interested in

Solve for x, where x is a real number.

Alex787 [66]

Hello!

First of all, let's undo the square roots by squaring both sides.

6x+2=9x-8

We subtract 9x from both sides.

-3x+2=-8

We subtract 2 from both sides.

-3x= -10

We divide both sides by -3.

x=10/3

I hope this helps!

7 0

2 years ago

Read 2 more answers

Hannah is giving her sister a softball for her birthday, and wants to put it in a cubic gift box to preserve the surprise. She w

Inga [223]

Answer:

B. E(s) = s^3 - 29.

Step-by-step explanation:

The amount of empty space $E(s)$ inside the cubic box is equal to the volume of the box minus the volume of the softball.

If the side length of the cubic box is $s$ , and the volume of the softball is $29in^3$ , then the amount of empty space $E(s)$ inside is

$E(s) = s^3-29$ ,

where $s^3$ is the volume of the cubic box.

Since it matches the equation we got above, choice B stands correct.

4 0

3 years ago

Solve the initial value problem yy′+x=x2+y2‾‾‾‾‾‾‾√ with y(1)=8‾√. To solve this, we should use the substitution u= x^2+y^2 help

leva [86]

Looks like the equation is

$yy'+x=\sqrt{x^2+y^2}$

Substitute $u(x)=x^2+y(x)^2$ , so that $u'=2x+2yy'$ . Then the equation is the same as

$\dfrac{u'-2x}2+x=\sqrt u\implies u'=2\sqrt u\implies\dfrac{\mathrm du}{2\sqrt u}=\mathrm dx$

Integrate both sides to get

$\sqrt u=C\implies\sqrt{x^2+y^2}=C$

Given that $y(1)=\sqrt8$ , we have

$\sqrt{1^2+(\sqrt8)^2}=C\implies C=3$

so the solution is

$\sqrt{x^2+y^2}=3$

7 0

3 years ago

8) Vicky jogged 3 miles in hour. What was her average rate of speed in miles ) per hour? SHOW YOUR WORK A) 7 12 B) 21 c) 21 D) 1

Arisa [49]

Answer: D.

Step-by-step explanation:

the ratio of 12/4 is the same as 3

6 0

3 years ago

Please help me !!!!!!

irinina [24]

Answer:

Use a cauculator :D

4 0

2 years ago