Answer:
10
Step-by-step explanation:
d = √(x2 -x1)² + (y2 - y1)²
√(-6 - 0)² + [1 - (-7)]²
√(-6)² + (8)²
√(36) + (64)
√100
= 10
First, 9.8 (Gravity) times 3 (time) equals 29.4, which is the velocity after 3 seconds. The kinematic equation for change in position that uses the variables we have is:
delta x= (v)(t) -0.5(acceleration)(time)^2
delta x= 29.4 times (3) - 0.5 (9.8) times 9
delta x= 44.1
100 minus 44.1 equals 55.9, which is the answer for part a.
Tell me if you need any clarification
PART B:
The kinematic equation for this is:
delta x= (initial velocity) times time plus 0.5 (a)(time)^2
100=(0)times(x) plus 0.5 (a)(time)^2
100=0.5(9.8)(x)^2
100=4.9x^2
100/4.9 is approxamitely 20.4.
The squareroot of this is approxamitely 4.5.
4.5 seconds
Tell me if you need any clarification
It's B because all the students that attended added together is 320 and 37.5 of 320 is 120
Answer:
Latoya:
cran : lem = 2 1/5 : 1 4/5
= 11/5 : 9/5
= 11 : 9
Lem : total = 9 : 20
Parker:
cran : lem = 2 1/2 : 3 1/2
= 5/2 : 7/2
= 5 : 7
Lem : total = 7 : 12
Step-by-step explanation:
In the problem with the white circle, x=100, in the problem with the blue circle, x might equal 165, but I'm not entirely certain. But I am certain about the first one.