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Aleonysh [2.5K]
3 years ago
15

In this triangle, side a = 24 units, side b = 10 units, and side c = 26 units. is this a right triangle?

Mathematics
2 answers:
egoroff_w [7]3 years ago
5 0
Yes, because 24^2 is 576 and 10^2 is 100. Together, its 676. And the square root of 26 is 676. So, yes it is a right triangle.
Anvisha [2.4K]3 years ago
3 0
If it is a right triangle then it must satisfy the Pythagorean Theorem:
 a²  +  b²  =  c²
24² + 10² = 26²
576 + 100 = 676
      676     = 676
           True

Answer: Yes. This is a right triangle.

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Which equation could represent a circle with a center located at (11,-5)
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The standard equation of a circle is:

(x-h)^2-(y-k)^2=r^2 where (h,k) is the center and r is the radius.

We need to make an equation of a circle, whose center is (11,-5) with any radius. Therefore, substitute the value.


(x-h)^2-(y-k)^2=r^2 \\ (11,-5)=(h,k) \\ (x-11)^2-(y-5)^2=64

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3 years ago
Square root of x plus 8 end root minus 6 equals x
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Answer:

Squaring both the sides, we get a quadratic and solving it, we find that the possible values of x are -7 and -4.

Step-by-step explanation:

The expression can be written as √(x+8) - 6 = x. Take 6 on the other side and square both the sides.

[√(x + 8)]² = (x + 6)²

x + 8 = x² + 12x + 36

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x = -7 and x = -4

The possible values of x are -7 and -4.

For more explanation, refer the following link:

brainly.com/question/10572241

#SPJ10

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