Answer:
Option(B),option(C) and Option(D) are the correct answer to the given question .
Explanation:
- In the option(B) if we apply the force to stop the car. The motion and force of car is in the opposite direction .Suppose the person is moving the car to the straight and person immediately apply break the back wheel of the car is stop this means that force and direction of motion is opposite that's why this is correct .
- In the option(C) the ball and batsman hinting the ball is in the opposite direction .Suppose the ball is coming to the batsman to the right and it hits to the left its a opposite direction Therefore in this the force and direction of motion is opposite that's why this is correct .
- In the option(D) if the person drawing water from a well there is always upward force is applied but there is always motion is there i.e downward force i,e mg.that's why force and direction of motion is opposite that's why this is correct .
- In the option(A) the force of opening the door of force and the motion is in the same direction therefore it is not the against the direction of motion that's why this option is incorrect .
The answer is vaporization, then condensation.
Here is a set of flash card that can help with this subject.
Explanation:
It is given that,
Mas of the object, m = 6 kg
It is lifted through a distance, h = 5.25 m
Tension in the string, T = 80 N
(a) By considering the free body diagram of the object, the forces can be equated as :
Work done by tension, 
(b) Work done by gravity, 
(c) Let v is the final speed of the object and u = 0
v = 5.91 m/s
Hence, this is the required solution.
The second major reason for the difference in gravity at differentlatitudes is that the Earth's equatorial bulge (itself also caused by centrifugalforce from rotation) causes objects at the Equator to be farther from the planet's centre than objects at the poles.
Answer:
1110 N
Explanation:
First, find the acceleration.
Given:
Δx = 300 m
v₀ = 85.5 km/h = 23.75 m/s
v = 0 m/s
Find: a
v² = v₀² + 2aΔx
(0 m/s)² = (23.75 m/s)² + 2a (300 m)
a = -0.94 m/s²
Find the force:
F = ma
F = (1180 kg) (-0.94 m/s²)
F = -1110 N
The magnitude of the force is 1110 N.
