The density of an object is the ratio of its mass over the volume. This translates to the amount of substance present in a certain space and can mathematically be expressed as,
density = mass / volume
In this item, we are given that the object of mass 1.41 kg is able to displace 0.314 L of liquid. The volume of water displaced is also the volume of the object. Hence,
density = 1.41 kg / 0.314 L = 4.49 kg/L
Then, we convert the calculated volume of g/mL.
density = (4.49 kg/L)(1 L / 1000 mL)(1000 g/1 kg)
<em> density = 4.49 g/mL</em>
Answer:
Explanation:
Let the specific heat of material be s
heat lost by material = m₁ s (T 1 - T ) , (T 1 - T ) is fall in temp , m₁ is mass of material
= .45 x s x (91 - 31.4 )
= 26.82 s
Heat gained by water
= m₂ cw (T2 - T )
1.3 x 4186 x ( 31.4 - 23 )
heat lost = heat gained
m₂ cw (T2 - T ) = m₁ s (T 1 - T )
1.3 x 4186 x ( 31.4 - 23 ) = .45 x s x (91 - 31.4 )
45711.12 = 26.82 s
s = 1704.36
Answer:
The temperature of the windings are 60.61 °C
Explanation:
Step 1: Data given
Resistance = 50 Ω
Temperature = 20.0 °C
After the motor has run for several hours the resistance rises to 58Ω.
Step 2: Calculate the new temperature
Formula: R = Rref(1 + α(T-Tref))
⇒with α = temperature coëfficiënt of Cupper at 20 °C = 0.00394/°C
⇒with Tref = reference temperature = 20°C
⇒with T = end temperature = TO BE DETERMINED
⇒with R = resistance at end temperature = 58Ω
⇒with Rref = resistance at reference temperature = 50 Ω
==> T = (R/Rref - 1)/α + Tref
T = (58/50) - 1 )/ 0.00394 + 20
T = 60.61 °C
The temperature of the windings are 60.61 °C
Answer:
755 x 10⁻⁷ m
Explanation:
D = distance of screen
=2. m
d is width of slit = ?
wave length λ = 566 nm
Width of central maxima = 2 λD /d
= 3.00 x 10⁻² =2 λD /d

= 754.67 x 10⁻⁷ m .
= 755x 10⁻⁷ m
Answer:
The temperature change per compression stroke is 32.48°.
Explanation:
Given that,
Angular frequency = 150 rpm
Stroke = 2.00 mol
Initial temperature = 390 K
Supplied power = -7.9 kW
Rate of heat = -1.1 kW
We need to calculate the time for compressor
Using formula of compression



Put the value into the formula


We need to calculate the rate of internal energy
Using first law of thermodynamics


Put the value into the formula


We need to calculate the temperature change per compression stroke
Using formula of rate of internal energy


Put the value into the formula


Hence, The temperature change per compression stroke is 32.48°.