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Tanya [424]
3 years ago
15

What is weight vs mass

Physics
1 answer:
Ray Of Light [21]3 years ago
8 0
Weight is the measurement of the pull of gravity on an object, while mass is the measurement of the amount of matter that an object contains.
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A titanium bicycle frame displaces 0.314 l of water and has a mass of 1.41 kg. what is the density of the titanium in g>cm3 ?
Kobotan [32]
The density of an object is the ratio of its mass over the volume. This translates to the amount of substance present in a certain space and can mathematically be expressed as,
 
                   density = mass / volume

In this item, we are given that the object of mass 1.41 kg is able to displace 0.314 L of liquid. The volume of water displaced is also the volume of the object. Hence,
                  density = 1.41 kg / 0.314 L = 4.49 kg/L

Then, we convert the calculated volume of g/mL.
                  density = (4.49 kg/L)(1 L / 1000 mL)(1000 g/1 kg)
                   <em>   density = 4.49 g/mL</em>
6 0
3 years ago
Read 2 more answers
An unknown material, m1 = 0.45 kg, at a temperature of T1 = 91 degrees C is added to a Dewer (an insulated container) which cont
goldenfox [79]

Answer:

Explanation:

Let the specific heat of material be s

heat lost by material = m₁ s (T 1 - T ) ,  (T 1 - T ) is fall in temp , m₁ is mass of material

= .45 x s x (91 - 31.4 )

= 26.82 s

Heat gained by water

= m₂ cw (T2 - T )

1.3 x 4186 x ( 31.4 - 23 )

heat lost = heat gained

m₂ cw (T2 - T ) = m₁ s (T 1 - T )

1.3 x 4186 x ( 31.4 - 23 ) =  .45 x s x (91 - 31.4 )

45711.12 = 26.82 s

s = 1704.36

7 0
4 years ago
The copper windings of a motor have a resistance of 50 Ω at 20° C when the motor is idle. After the motor has run for several ho
Drupady [299]

Answer:

The temperature of the windings are 60.61 °C

Explanation:

Step 1: Data given

Resistance = 50 Ω

Temperature = 20.0 °C

After the motor has run for several hours the resistance rises to 58Ω.

Step 2: Calculate the new temperature

Formula: R = Rref(1 + α(T-Tref))

⇒with α = temperature coëfficiënt of Cupper at 20 °C = 0.00394/°C

⇒with Tref = reference temperature = 20°C

⇒with T = end temperature = TO BE DETERMINED

⇒with R = resistance at end temperature = 58Ω

⇒with Rref = resistance at reference temperature =  50 Ω

==> T = (R/Rref - 1)/α + Tref  

T = (58/50) - 1 )/ 0.00394 + 20

   T = 60.61 °C

The temperature of the windings are 60.61 °C

5 0
4 years ago
Green light (λ = 566 nm) strikes a single slit at normal incidence. Part A
VARVARA [1.3K]

Answer:

755 x 10⁻⁷ m

Explanation:

D = distance of screen

=2.  m

d is width of slit = ?

wave length λ = 566 nm

Width of central maxima = 2 λD /d

= 3.00 x 10⁻² =2 λD /d

d=\frac{2\times566\times10^{-9}\times2}{3\times10^{-2}}

= 754.67 x 10⁻⁷ m .

= 755x 10⁻⁷ m

8 0
3 years ago
A reciprocating compressor is a device that compresses air by a back-and-forth straight-line motion, like a piston in a cylinder
Stella [2.4K]

Answer:

The temperature change per compression stroke is 32.48°.

Explanation:

Given that,

Angular frequency = 150 rpm

Stroke = 2.00 mol

Initial temperature = 390 K

Supplied power = -7.9 kW

Rate of heat = -1.1 kW

We need to calculate the time for compressor

Using formula of compression

\terxt{time for compression}=\text{time for half revolution}

\terxt{time for compression}=\dfrac{1}{2}\times T

\terxt{time for compression}=\dfrac{1}{2}\times \dfrac{1}{f}

Put the value into the formula

\terxt{time for compression}=\dfrac{1}{2}\times \dfrac{1}{150}\times60

\terxt{time for compression}=0.2\ sec

We need to calculate the rate of internal energy

Using first law of thermodynamics

U=Q-W

\dfrac{\Delta U}{\Delta t}=\dfrac{\Delta Q}{\Delta t}-\dfrac{\Delta W}{\Delta t}

Put the value into the formula

\dfrac{\Delta U}{\Delta t}=(-1.1)-(7.9)

\dfrac{\Delta U}{\Delta t}=6.8\ kW

We need to calculate the temperature change per compression stroke

Using formula of rate of internal energy

\dfrac{\Delta U}{\Delta t}=\dfrac{nc_{v}\Delta \theta}{\Delta t}

\Delta\theta=\dfrac{\Delta U}{\Delta t}\times\dfrac{\Delta t}{n\times c_{c}}

Put the value into the formula

\Delta \theta=6.8\times10^{3}\dfrac{0.2}{2.0\times20.93}

\Delta\theta=32.48^{\circ}

Hence, The temperature change per compression stroke is 32.48°.

6 0
4 years ago
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