Question

Б) 3х2 – 10 = 152how to solve with square root​

Answer 1

Answer:

$3\sqrt{6}$  and  $-3\sqrt{6}$

Step-by-step explanation:

We will take numbers to one side and variables to one side eliminate the "Square" with "Square Root" and solve for the variable x. The process is shown below:

$3x^2-10=152\\3x^2=152+10\\3x^2=162\\x^2=\frac{162}{3}\\x^2=54\\x=\sqrt{54}$

Now, we need to reduce the radical by using the rule shown below:

$\sqrt{x*y}=\sqrt{x} \sqrt{y}$

Now,

$\sqrt{54}=\sqrt{6*9} =\sqrt{6} \sqrt{9} =3\sqrt{6}$

The correct answer is  $3\sqrt{6}$ and $-3\sqrt{6}$

Note: squaring positive and negative makes the same answer