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2 years ago

5

Helppp please!!! with the equation, i have no clue

1 answer:

Artist 52 [7]2 years ago

7 0

Answer:

look at the picture i have sent

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3 years ago

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My ones digit is twice the hundreds digit

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The hundreds digit is twice as large as the ones digit. 3 doubled is 6, 6 doubled is 12, and 9 doubled is 18. Since 6 is the only option that is one digit, the hundreds digit must be 6 and the ones digit must be 3. The tens digit is five less than the hundreds digit.

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2 years ago

What is the common factor of each term in the expression 2b+5b?

S_A_V [24]

The common factor is b since it is divisible by both 2b and 5b

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2 years ago

Any help would be appreciated. Thank you!

trapecia [35]

Answer:

Area $=62.5\sqrt{6}$ square units

$AB=5\sqrt{15}$ units

$BC=5\sqrt{10}$ units

Step-by-step explanation:

In a right triangle the altitude drawn to the hypotenuse is the geometric mean of the segments at which this altitude divides the hypotenuse.

So,

$BD^2=15\cdot 10\\ \\BD^2=150\\ \\BD=\sqrt{150}=5\sqrt{6}\ units$

a. The area of the triangle ABC is

$A_{ABC}=\dfrac{1}{2}\cdot BD\cdot AC=\dfrac{1}{2}\cdot 5\sqrt{6}\cdot (15+10)=\dfrac{125\sqrt{6}}{2}=62.5\sqrt{6}\ un^2.$

b. The legs of the right triangle are geometric means of the segment adjacent to this leg and the hypotenuse, so

$AB^2=AD\cdot AC=15\cdot 25\Rightarrow AB=5\sqrt{15}\ units\\ \\BC^2=CD\cdot AC=10\cdot 25\Rightarrow BC=5\sqrt{10}\ units$

5 0

3 years ago

Nadia plans to paint her jewelry box. The box is shaped like a rectangular prism with the dimensions

Pachacha [2.7K]

Answer:

$132\ in^{2}$ is closest to the total surface area of the box

Step-by-step explanation:

we know that

The surface area of the box is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the box

we have

$L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in$

$W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in$

$H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in$

<em>Find the area of the base B</em>

$B=LW$

$B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}$

<em>Find the perimeter of the base P</em>

$P=2(L+W)$

$P=2(\frac{31}{4}+\frac{13}{4}))$

$P=2(\frac{44}{4})=22\ in$

<em>Find the surface area</em>

$SA=2(\frac{403}{16})+22(\frac{31}{8})$

$SA=(\frac{403}{8})+(\frac{682}{8})$

$SA=\frac{1,085}{8}=135.625\ in^{2}$

6 0

3 years ago