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Iteru [2.4K]
3 years ago
14

What is i^85 HELP PLEASE!!!!!!!!!!!!!

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0

Answer:

the answer to your question is b

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Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1
Lera25 [3.4K]
Assuming the function is

f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}

For f(x) to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)
\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)
\iff2=b+c

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

f'(x)=\begin{cases}2&\text{for }x1\end{cases}

\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)
\iff2=2b+c

Now we solve for b and c:

\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2
5 0
3 years ago
A food factory produces trail mix containing raisins and cashews at a cost of $9 per pound. Every 3 pound container of trail mix
Svetllana [295]

Answer:

4r+8c = 27

Step-by-step explanation:

consider that 3 lbs will cost $27 at $9/lb

so, adding up the value of the raisins and cashews in a 3lb bag.

7 0
3 years ago
What is the product of 8.4 times the quantity of 10 raised to the power of 7
TEA [102]
84,000,000 is the answer
6 0
3 years ago
Perform the indicated operation. -8 + (-4)
Lostsunrise [7]

It is -12, negative + negative is Negative unless if its with a positive it will cancel out

ex, -12 + 6= -6

3 0
3 years ago
Please help!!!!
koban [17]

Answer:

Correct choice is A

Step-by-step explanation:

If a function has an inverse, then there is at most one x-value for each y-value.

The tangent function is periodic with period \pi. Hence, at each value for which f(x)=\tan x is defined, f(x+n\pi )=\tan x for each integer n. Therefore, the function f(x)=\tan x does not have an inverse. Since tangent is not a one-to-one function, the domain must be limited. From examining the graph of the tangent function, we see that in each interval of the form

\left((2k−1)\dfrac{\pi}{2},(2k+1)\dfrac{\pi}{2}\right)

where k is an integer, the tangent function assumes every value in its range. Moreover, in each such interval, each y-value is achieved exactly once. Hence, we can create an invertible function by restricting the domain tangent function to one such interval. Such interval is an interval between two consecutive vertical asymptotes x=(2k−1)\dfrac{\pi}{2} and x=(2k+1)\dfrac{\pi}{2}.

4 0
2 years ago
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