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ioda
2 years ago
9

Factorisation of 4x^2-5x-1

Mathematics
1 answer:
max2010maxim [7]2 years ago
3 0
I am not sure but it is right if your question is right.

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Deacon wants to order DVDs. Each DVD costs $12.95, and he must pay a shipping and handling fee of $4.95 for the entire order. De
eduard

Answer:

12.95a + 4.95 ≤ 75

Step-by-step explanation:

Given:

Cost of each DVD = $12.95

Total shipping fee = $4.95

Total amount as gift card = $75

Find;

Inequality

Computation:

Assume;

Number of DVD he purchase = a

So,

Total amount as gift card ≥ (Cost of each DVD)(Number of DVD he purchase ) + Total shipping fee

75 ≥ (12.95)(a) + 4.95

12.95a + 4.95 ≤ 75

6 0
2 years ago
Determine if the side lengths 6, 11, and 19 form a triangle. If it is a triangle, classify it by its sides.
Butoxors [25]
It is not triangle because the one side of triangle should be smaller than the other two sides
Let's check
6+11=17
17<19
Or
11+19=31
9<31
4 0
3 years ago
Determine whether the function f(x) = -9.5 + 6 + x² is even, odd or neither.
zimovet [89]

Answer:

The function f(x) = -9.5 + 6 + x² is neither odd or even.

Step-by-step explanation:

We know that a function is termed as 'even' when

f(-x) = f(x) for all x

We know that a function is termed as 'odd' when

f(-x) = -f(x) for all x

Given the function

f(x) = -9.5x⁵ + 6 + x²

substitute x with -x

f(-x) = -9.5(-x)⁵ + 6 + (-x)²

as (-x)⁵ = -x⁵, so

f(-x) = -(-9.5x)⁵ + 6 + (-x)²

Apply exponent rule: (-a)ⁿ = aⁿ, if n is even

f(-x) = -(-9.5x)⁵ + 6 + x²

Apply rule: -(-a) = a

f(-x) = 9x⁵ + 6 + x²

As

f(-x) ≠ f(x) ≠ -f(x)

Therefore, the function f(x) = -9.5 + 6 + x² is neither odd or even.

5 0
3 years ago
Sophia bought 3 yards of trim to put around a rectangular scarf. She wants the width of the scarf to be a whole number that is a
Helen [10]
I believe the answer is 24.You do 12 divided by 3 and then you get 4. Then you do 4 times 6 and get 24.
3 0
2 years ago
Help ill give 5 stars if correct
Step2247 [10]

Answer:

7 1/4

Step-by-step explanation:

12 3/4- 5 1/2

4 0
2 years ago
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