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zepelin [54]
3 years ago
5

Electron configuration assignment pleaseee help asappp its 100 points and I give out brainly <3

Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
7 0

Answer:

https://chem.libretexts.org/Bookshelves/Physical_and_Theoretical_Chemistry_Textbook_Maps/Supplemental_Modules_(Physical_and_Theoretical_Chemistry)/Quantum_Mechanics/10%3A_Multi-electron_Atoms/Electron_Configuration

Explanation:

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For which applications would you choose liquid over gas or solid
nekit [7.7K]

Answer:

volume

Explanation:

i think its right

5 0
3 years ago
How does a sample of water at 38 °C compare to a sample of water at 295 K?
Sidana [21]

Converting the temperature, 295 K from Kelvin to Celsius scale:

295 K - 273 = 22^{0} C

Water has a boiling point of 100^{0}C and a melting point of 0^{0} C

When we compare water at two different temperatures, 22^{0}C and 38^{0}C we can say that water is in liquid form at both these temperatures as both of them are quite below the boiling temperature and above the melting temperature.

The temperature difference between water at the given two temperatures = 38^{0}C - 22^{0}C = 16^{0}C

Water at 38^{0}C is at a higher temperature and so is warmer than water at a lower temperature of 22^{0}C (or 295 K).


7 0
3 years ago
In terms of disorder and energy, systems in nature have a tendency to undergo changes toward
Simora [160]

Answer:

Option C is correct

Explanation:

Entropy is defined as the randomness in a system. In nature, a system tends to have high entropy. The higher the entropy , the spontaneous the reactions would be. As a system loses energy, it becomes more ordered and less random. Hence, as the reaction proceeds in a system, the system  has higher energy/entropy and less order.  

Hence, option c is correct

8 0
4 years ago
1. What is the relationship between the concentration of the hydronium and hydroxide
Hitman42 [59]

Answer:

- Neutral solutions: concentration of hydronium equals the concentration of hydroxide.

- Acid solutions: concentration of hydronium is greater than the concentration of hydroxide.

- Basic solutions concentration of hydronium is lower than the concentration of hydroxide.

Explanation:

Hello,

It is widely known that the pH of water is 7, therefore the pOH of water is also 7 based on:

pH+pOH=14

In such a way, we can compute the concentration of hydronium and hydroxide ions as shown below:

pH=-log([H^+])\\

[H^+]=10^{-pH}=10^{-7}=1x10^{-7}M

pOH=-log([OH^-])

[OH^-]=10^{-pOH}=10^{-7}=1x10^{-7}M

Thus, we notice that the relationship between the concentration of the hydronium is equal for water or neutral solutions. Moreover, if we talk about acid solutions, pH<OH therefore the concentration of hydronium is greater than the concentration of hydroxide. On the other hand if we talk about basic solutions, pH>OH therefore the concentration of hydronium is lower than the concentration of hydroxide.

Best regards.

4 0
3 years ago
A laboratory analysis of a 100 g sample finds it is composed of 1.8 g hydrogen, 56.1 g sulfur, and 42.1 g oxygen. What is its em
Neporo4naja [7]

Answer: The empirical formula is H_2S_2O_3

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mas of H = 1.8 g

Mass of S = 56.1 g

Mass of O = 42.1 g

Step 1 : convert given masses into moles.

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.8g}{1g/mole}=1.8moles

Mass of S =\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{56.1g}{32g/mole}=1.8moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{42.1g}{16g/mole}=2.6moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For H = \frac{1.8}{1.8}=1

For S = \frac{1.8}{1.8}=1

For O =\frac{2.6}{1.8}=1.5

Converting to whole number ratios

The ratio of H: S: O= 2: 2: 3

Hence the empirical formula is H_2S_2O_3

7 0
3 years ago
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