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lyudmila [28]
3 years ago
5

A compound has an empirical formula of SO3 and a molecular mass of 152. What is the molecular formula?

Chemistry
1 answer:
Anettt [7]3 years ago
5 0

Answer:

Molecular formula = S₂O ₆

Explanation:

Given data:

Empirical formula = SO₃

Molecular formula = ?

Molecular mass = 152 g/mol

Solution:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  = 80 g/mol

n = 152 g/mol / 80 g/mol

n = 2

Molecular formula = n (empirical formula)

Molecular formula = 2(SO₃)

Molecular formula = S₂O ₆

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aleksklad [387]

Ionic equation:

\text{H}_2\text{PO}_4^{-} + \text{HAsO}_4^{2-} \to \text{HPO}_4^{2-} + \text{H}_2\text{AsO}_4^{-}

The acid and base in a conjugate pair differ by only one proton \text{H}^{+}. The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.

\text{H}_2\text{PO}_4^{-} loses one proton to produce \text{HPO}_4^{2-} in this reaction.

\text{H}_2\text{PO}_4^{-} \to \text{H}^{+} + \text{HPO}_4^{2-}

Meanwhile, \text{HAsO}_4^{2-} gains one proton to form \text{H}_2\text{AsO}_4^{-}.

\text{HAsO}_4^{2-} + \text{H}^{+} \to \text{H}_2\text{AsO}_4^{-}

Therefore

  • \text{H}_2\text{PO}_4^{-} is the conjugate acid  \text{HPO}_4^{2-}, its conjugate base.
  • \text{HAsO}_4^{2-} is the conjugate base of \text{H}_2\text{AsO}_4^{-}, its conjugate acid.
8 0
3 years ago
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Sodium metal reacts with water to produce hydrogen gas.
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Answer:

Explanation:

Question 6 options:

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2 years ago
How much energy is required to raise the temperature of 3 kg of iron from 20° C to 25°C? Use the table below and this equation:
ElenaW [278]

The energy required to raise the temperature of 3 kg of iron from 20° C to 25°C is 6,750 J( Option B)

<u>Explanation:</u>

Given:

Specific Heat capacity of Iron= 0.450 J/ g °C

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Required Energy to raise the Temperature

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Amount of energy required is given by the formula,

Q = mC (ΔT)

Solution:

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So 3 kg = 3000 g

C = specific heat of iron = 0.450 J/ g °C [ from the given table]

ΔT = change in temperature = 25° C - 20°C = 5°C

Plugin the values, we will get,

Q = 3000 g ×  0.450 J/ g °C ×  5°C

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So the energy required is 6,750 J.

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