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BlackZzzverrR [31]
3 years ago
8

What is the molarity of a solution containing 0.32 moles of NaCI in 3.4 liters

Chemistry
1 answer:
CaHeK987 [17]3 years ago
3 0

Answer:

.094 M

Explanation: 0.32molNaCl/ 3.4L = .094M

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Please answer!! I’ll make brainliest!!
Alenkinab [10]

Answer:

greater than 115 N upwards

Explanation:

3 0
3 years ago
(will give brainliest) show your work. How many grams of Copper(I) nitrate, CuNO3 are required to produce 88.0 grams of aluminum
ValentinkaMS [17]

Based on the stoichiometry of the reaction, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

<h3>What is stoichiometry of a reaction?</h3>

The stoichiometry of a reaction is the molar ratio in which reactants combine to form products.

The stoichiometry of the reaction shows that 6 moles of copper (i) nitrate produces 2 moles of aluminium nitrate.

molar mass of Copper(I) nitrate, CuNO3 = 126 g

molar mass of aluminum nitrate, Al(NO3)3 = 213 g

88.0 g of aluminum nitrate, Al(NO3)3 = 88.0/213 moles = 0.413 moles

0.413 moles of Al(NO3)3 will be produced by 0.413 ×6/3 = 1.239 moles of CuNO3

Mass of 1.239 moles of CuNO3 = 1.239 × 126 = 156.114 g of CuNO3

Therefore, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

Learn more about stoichiometry at: brainly.com/question/16060223

Therefore, 156.114 g of CuNO3

4 0
2 years ago
If you find that a substance turns litmus paper to blue and contains hydrogen ions it is most likely what
Darya [45]
An acid, possibly a strong one
4 0
3 years ago
What is the net ion charge of Beryllium?​
KATRIN_1 [288]

Explanation:

Beryllium is a group 2 element and its atomic number is 4. Electronic configuration of beryllium is 1s^{2}2s^{2}.

Since, a beryllium contains two valence electrons so, in order to attain stability it will readily lose its 2 valence electrons.

Therefore, a beryllium atom upon losing two valence electrons will acquire a +2 charge.

Thus, we can conclude that the net ion charge of Beryllium is +2.

7 0
3 years ago
How can you tell from the name the types of bonds present in a hydrocarbon?
Darya [45]

Answer:

Alkane

Alkene

Alkyne

Explanation:

Alkane=1 bond (Saturated hydrocarbon)

Alkene= 2 bonds (Unsaturated hydrocarbon)

Alkyne= triple bonds (Unsaturated hydrocarbon)

Formula of Alkane = CnH2n+2

Formula of Alkene = CnH2n

Formula of Alkyne = CnH2n-2

7 0
3 years ago
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