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3 years ago

Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products.

Chemistry

1 answer:

UNO [17]3 years ago

4 0

Explanation:

Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:

Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.

Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.

However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.

Elimination of the hydrogen from the methyl group is easier.

Thus, the major product will A

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Answer:

1. D excess fertilizer use

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3 years ago

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Answer:

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3 years ago

Suppose a substance has a heat of fusion equal to 45 calg and a specific heat of 0.75

Varvara68 [4.7K]

Answer:

The substance will be in liquid state at a temperature of 97.3 °C

Note: The question is incomplete. The complete question is given below :

Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0.75 cal/g°C in the liquid state. If 5.0 kcal of heat are applied to a 50 g sample of the substance at a temperature of 24°C, what will its new temperate be? What state will the sample be in? (melting point of the substance = 27°C; specific heat of the solid =0.48 cal/g°C; boiling point of the substance = 700°C)

Explanation:

1.a) Heat energy required to raise the temperature of the substance to its melting point, H = mcΔT

Mass of solid sample = 50 g; specific heat of solid = 0.75 cal/g; ΔT = 27 - 24 = 3 °C

H = 50 × 0.75 × 3 = 112.5 calories

b) Heat energy required to convert the solid to liquid at its melting point at 27°C, H = m×l, where l = 45 cal/g

H = 50 × 45 = 2250 cal

c) Total energy used so far = 112.5 cal + 2250 cal = 2362.5 calories.

Amount of energy left = 5000 - 2362.5 = 2637.5 cal

The remaining energy is used to heat the liquid

H = mcΔT

Where specific heat of the liquid, c = 0.75 cal/g/°C, H = 2637.5 cal, ΔT = temperature change

2637.5 = 50 × 0.75 x ΔT

ΔT = 2637.5 / ( 50*0.75)

ΔT = 70.3 °C

Final temperature of sample = (70.3 + 27) °C = 97.3 °C

The substance will be in liquid state at a temperature of 97.3 °C

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3 years ago

What is the scientific method?

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D. A set of steps that help scientists gather knowledge

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3 years ago

A piece of metal ore has a density of 1.72 g/mL. When a student places it into a graduated cylinder containing water, the liquid

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Answer:

Explanation:

Since..., Density = mass/volume

;Firstly calculate the volume change of the water when the metal is placed in,

;Volume = 26.47 - 21.25

;Volume = 5.22 mL

Hence the mass of the ore;

; Making mass the subject of formula in the above equation,

Mass = Density × Volume

; Mass = 1.72 × 5.22

; Hence the mass = 8.9784

= 9g

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4 years ago