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Varvara68 [4.7K]
3 years ago
8

HURRY! HELP PLS

Mathematics
1 answer:
Elodia [21]3 years ago
5 0
Answer: You can conclude that the medication is effective and decreases sneezing
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A variable needs to be eliminated to solve the system of equations below. Choose the
notsponge [240]

Answer:

x=-2

y= 8

Step-by-step explanation:

Given data

10x – 2y = -36-----------1

7x – 2y = -30--------------2

-Subtract to eliminate y

3x-0= -6

3x= -6

x= -6/3

x= -2

Put x= -2 in

7(-2)– 2y = -30

-14-2y=-30

-14+30=2y

16=2y

y= 16/2

y= 8

8 0
3 years ago
Find the infinite sum of 10,5,2.5,1.25...
____ [38]
Notice this is a geometric progression since each number multiplied by some factor equals the next number in the sequence, in this case,

10 \times r = 5 \Rightarrow r=0.5

Then by applying the formula for sum to infinity of a geometric progression,
S_\infty = \frac{a}{1-r} = \frac{10}{1-0.5} = 20
3 0
3 years ago
Read 2 more answers
A certain radioactive material decays in such a way that the mass in kilograms remaining after t years is given by the function
Angelina_Jolie [31]

The mass of radioactive material remaining after 50 years would be 48.79 kilograms

<h3>How to determine the amount</h3>

It is important to note that half - life is the time it takes for the amount of a substance to reduce by half its original size.

Given the radioactive decay formula as

m(t)=120e−0.018t

Where

t= 50 years

m(t) is the remaining amount

Substitute the value of t

m(t) = 120e^-^0^.^0^1^8^(^5^0^)

m(t) = 120e^-^0^.^9

Find the exponential value

m(t) = 48.788399

m(t) = 48.79 kilograms to 2 decimal places

Thus, the mass of radioactive material remaining after 50 years would be 48.79 kilograms

Learn more about half-life here:

brainly.com/question/26148784

#SPJ1

7 0
2 years ago
Please answer these two questions..
madam [21]
1. 2t-2i
2. 6ab2(square)
8 0
3 years ago
I am stuck on this will give brainest
Cloud [144]

Answer:

Step-by-step explanation:

21. (24)(2)/6+4=48

=48/6+4

=8+4

=12

6 0
3 years ago
Read 2 more answers
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