There are many ways, but here is one:
x = 100
Since ‘x’ is 100 and we want 100 more, we just need to add ‘x’ to 623
Answer: x + 623 (Make sure you define your ‘x’ value)
Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
Answer:
The answer is a. both open upward; h is wider than f
Step-by-step explanation:
Slope: −2
y-intercept: (0,1)
Answer:
