Question

Need help on 12...have to find the area..teacher said to use pythagreoum(how ever u spell it) theorem

Answer 1

Answer:

58$\sqrt{65}$

Step-by-step explanation:

you can find the height of this trapezoid by using the pythagorean theorem where the hypotenuse is 18 and one leg is 8 (33-25)

let x = height

$8^{2}$ + $x^{2}$ = $18^{2}$

$x^{2}$ = 324 - 64

$x^{2}$ = 260     therefore, x = $\sqrt{260}$

$\sqrt{260}$ = $\sqrt{4}$· $\sqrt{65}$  or  2$\sqrt{65}$

A = $\frac{1}{2}$h x (sum of the bases)        

 

bases are 25 and 33

A = (2$\sqrt{65}$) ÷ 2)58