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Maslowich
4 years ago
13

It is what it is ffmijcnrfchnejidxmjked uh rfj9iow,xoecnrubcyemxwkxm

Mathematics
2 answers:
I am Lyosha [343]4 years ago
5 0

Answer:

wallpaper lol :))))) it's cool tho

Vesna [10]4 years ago
3 0

Answer:

ok but this shii is fire ash

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Consider the sequence.
kirza4 [7]
I wish I can’t help but lol k bye
5 0
3 years ago
Translate the sentence into an equation.
SpyIntel [72]
7+(w+3)=5
This is the answer to your question
6 0
3 years ago
The perimeter of a rectangle is 70cm.
Pavlova-9 [17]

Answer:

11 ALSO SOMEONE PLS ANSWER MY QUESTION

Step-by-step explanation:

24+24=48

70-48=22

22/2=11

4 0
3 years ago
Representar las rectas a, b y c y determinar si son paralelas (o perpendiculares) dos a dos. A: y=−3x+5 | b: y =x/3+2 | c: y=−3x
Anettt [7]

Answer:

A y C: paralelas

B y A: perpendiculares

B y C: perpendiculares.

Step-by-step explanation:

Sea una recta:

f(x) = a*x + b

Donde a es la pendiente y b es la ordenada al origen.

Otra recta va a ser paralela a esta si tiene la misma pendiente, pero una diferente ordenada al origen, por ejemplo:

g(x) = a*x + c

Y una recta perpendicular a f(x) tendría una pendiente p = -(1/a)

Entonces podemos escribir la línea perpendicular a f(x) como:

h(x) = -(1/a)*x + c

Ahora veamos nuestras líneas:

A(x) =  y = −3*x+5

B(x) = y = x/3+2 = (1/3)*x + 2

C(x) = y = -3*x + 1

Primero veamos cuáles son paralelas:

A(x) y C(x) tienen la misma pendiente (-3) y diferente ordenada al origen, entonces  A y C son paralelas.

Sabiendo que la pendiente de A y C es -3, una línea perpendicular a esta tendría una pendiente:

-(1/-3) = 1/3

Que es justamente la pendiente que tiene la línea B, entonces podemos concluir que B es perpendicular a las líneas A y C.

A y C: paralelas

B y A: perpendiculares

B y C: perpendiculares.

7 0
3 years ago
The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista
baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{10.634 - \mu}{\sigma}

10.634 - \mu = 1.28\sigma

\mu = 10.634 - 1.28\sigma

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

Z = \frac{X - \mu}{\sigma}

-1.96 = \frac{9.7565 - \mu}{\sigma}

9.7565 - \mu = -1.96\sigma

\mu = 9.7565 + 1.96\sigma

We also have that:

\mu = 10.634 - 1.28\sigma

So

10.634 - 1.28\sigma = 9.7565 + 1.96\sigma

1.96\sigma + 1.28\sigma = 10.645 - 9.7565

3.24\sigma = 0.8885

\sigma = \frac{0.8885}{3.24}

\sigma = 0.2742

The mean is

\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0
4 years ago
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