Question

What is the equation of the line that is parallel to the given line and passes theought the point (12, -2)

Answer 1

Answer:

Option D (y = 5/6x -12).

Step-by-step explanation:

Hey there!

The equation of the line which passes through the point (12,-2) is (y+2) = m2(x-12)………(i) [Using one point formula].

According to the question, the first line passes through point (12,6) and (0,-4).

So,

$slope(m1) = \frac{y2 - y1}{x2 - x1}$

$or \: m1 = \frac{ - 4 - 6}{0 - 12}$

$or \: m1 = \frac{5}{6}$

Therefore, the slope of the line is 5/6.

Now as per the condition of parallel lines, m1 =m2 = 5/6.

So, keeping the value of m2 in equation (i), we get;

(y+2) = 5/6(x-12)

$y + 2 = \frac{5}{6} x - 10$

or, y = 5/6x - 12.

Therefore, the required equation is y = 5/6 X - 12.

Hope it helps!