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Elis [28]
3 years ago
15

What is the equation of the line that is parallel to the given line and passes theought the point (12, -2)

Mathematics
1 answer:
Nesterboy [21]3 years ago
3 0

Answer:

<u>Option </u><u>D</u> (y = 5/6x -12).

Step-by-step explanation:

Hey there!

The equation of the line which passes through the point (12,-2) is (y+2) = m2(x-12)………(i) [Using one point formula].

According to the question, the first line passes through point (12,6) and (0,-4).

So,

slope(m1) =  \frac{y2 - y1}{x2 - x1}

or \: m1 =  \frac{ - 4 - 6}{0 - 12}

or \: m1 =   \frac{5}{6}

Therefore, the slope of the line is 5/6.

Now as per the condition of parallel lines, m1 =m2 = 5/6.

So, keeping the value of m2 in equation (i), we get;

(y+2) = 5/6(x-12)

y + 2 =  \frac{5}{6} x - 10

or, y = 5/6x - 12.

Therefore, the required equation is y = 5/6 X - 12.

<u>Hope</u><u> </u><u>it </u><u>helps</u><u>!</u>

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