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Luda [366]
3 years ago
14

Different size containers. Tanner used for storing dry goods. The largest container held 12 /3/4 cups of dry goods. 2/3 of the a

mount in container a, 2/3 of the amount in container b. What was the total amount in cups of dry goods. That tanner could store in all three containers
Mathematics
1 answer:
Darya [45]3 years ago
7 0

Answer:

29 3/4 cups

Step-by-step explanation:

total amount of tanner in the 3 containers = sum of tanners in each container

total cups in containers b and c = 2/3 x 12 3/4

2/3 x 51/4 = 17/2 cups or 8 1/2 cups

total capacity = 8 1/2 + 8 1/2 + 12 3/4 = 17 + 12 3/4 = 29 3/4

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The system of equations y=4x y-4=4 (x-1) has.
Alekssandra [29.7K]

Answer:

infinitely many solutions.

Step-by-step explanation:

y=4x

y-4=4 (x-1)

Lets substitute the first equation into the second equation.

4x -4 = 4(x-1)

Distribute

4x-4 = 4x-4

Subtract 4x from each side

4x-4x-4 =4x-4x-4

-4=-4

This is always true.  X can be anything.  We have infinite solutions

6 0
3 years ago
Read 2 more answers
What is the slope of the line represented by the equation y = -1/2x +1/4?
ELEN [110]

Answer:

-1/2

Step-by-step explanation:

y = -1/2x + 1/4 is in slope y-intercept form : y = mx + b

m is slope

Slope = -1/2

4 0
3 years ago
100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!
Volgvan

Using weighed averages, it is found that:

  1. The final grade is 91.
  2. The final grade is 66.8.
  3. The higher grade would be 79.55, with the second grading scheme.
  4. On average, she sold $48,280 per day.
  5. On average, she makes $12.5 per hour.

---------------------------------------

To find the weighed average, we multiply each value by it's weight.

---------------------------------------

Question 1:

  • Grade of 91, with a weight of 67%.
  • Grade of 91, with a weight of 33%.

Thus:

F = 91\times0.67 + 91\times0.33 = 91

The final grade is 91.

---------------------------------------

Question 2:

  • Grade of 83, with a weight of 40%(highest grade).
  • Grade of 60, with a weight of 30%.
  • Grade of 52, with a weight of 30%.

Thus:

F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8

The final grade is 66.8.

---------------------------------------

Question 3:

With teacher 1:

  • 75 with a weight of 25%.
  • 80 with a weight of 10%.
  • 85 with a weight of 40%.
  • 62 with a grade of 25%.

Thus:

F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25

---------------------------------------

With teacher 2:

  • 75 with a weight of 15%.
  • 80 with a weight of 10%.
  • 85 with a weight of 60%.
  • 62 with a weight of 15%.

Thus:

F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55

The higher grade would be 79.55, with the second grading scheme.

---------------------------------------

Question 4:

  • Average of $36,432, with a weight of \frac{3}{3+10} = \frac{3}{13}
  • Average of $51,834, with a weight of \frac{10}{13}

Thus:

A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280

On average, she sold $48,280 per day.

---------------------------------------

Question 5:

  • Average of $14.84, with a weight of \frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}
  • Average of $10.76, with a weight of \frac{4}{7}

Thus:

A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353

5 0
3 years ago
Given: BC = 10 inches
RUDIKE [14]

Answer:

area of sector BCD =60/360×π×10²=52.36ft²

a area of sector ADC =90/360×π×√50²=39.27ft²

actual <u>area</u><u> </u><u>=</u><u>5</u><u>2</u><u>.</u><u>3</u><u>6</u><u>ft²-39</u><u>.</u><u>2</u><u>7</u><u>f</u><u>t</u><u>²</u><u>=</u><u>1</u><u>3</u><u>.</u><u>0</u><u>9</u><u>=</u><u>1</u><u>3</u><u>ft²</u>

4 0
3 years ago
Which of the following is a polynomial with roots - square root of 5, - square root of five and 3
valina [46]

Answer:

A is correct

Step-by-step explanation:

What we need to do here is to multiply all the roots together

The roots are;

3, √5 and -√5

Let’s have them in form of a sum

if x = 3, then the root is x-3

If x = √5, then the root is x-√5

If x = -√5, then the root is x+ √5

Now we need to multiply all these together to arrive at the original polynomial

Let’s start by using the roots

(x-√5)(x+ √5)

we can use the difference of 2 squares here and we arrive at (x^2 -5)

So finally, the polynomial would be;

(x^2-5)(x-3)

= x(x^2-5) -3(x^2-5)

= x^3-5x-3x^2+15

By rearranging, we have;

x^3-3x^2-5x+15

4 0
3 years ago
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