Scale factor is given by:
(length of larger figure)/(length of smaller figure)=(width of larger figure)/(width of the smaller figure)=3.4
The length of the larger figure will be given by:
length=(scale factor)*(length of smaller figure)
=3.4*6=20.4 cm
width of the larger figure will be given by:
width=(scale factor)*(width of smaller figure)
=3.4*4.5
=15.3 cm
Therefore the dimension of the new parallelogram will be 20.4 cm by 15.3 cm
Answer:
f⁻¹(x) = (1/2)x +5
Step-by-step explanation:
In y = f(x), swap the variables, then solve for y. The expression you get is f⁻¹(x).
... y = 2x -10
... x = 2y -10 . . . . . . swapped variables
... x +10 = 2y . . . . . add 10
... (1/2)x + 5 = y . . . . divide by 2
... f⁻¹(x) = (1/2)x + 5 . . . . . . rewrite using function notation
Answer:
25.5
Step-by-step explanation:
first find the area od the rectangle than the triangle.
to find the area count the number of squares and use A=b*h
than do the same for the triangle using A=.5*b*h
15=3*5
10.5=.5*3*7
10.5+15=25.5
Answer:
(a) Number of inches that have burned from the candle since it was lit is (1.1t) inches
(b) The remaining length of the candle is (16 - 1.1t) inches
Step-by-step explanation:
(a). Length of candle before it was lit = 16 inches
Constant rate at which at which candle burns = 1.1 inches per hour
Let t represent the number of hours that have elapsed since the candle was lit
In 1 hour, 1.1 inches of the candle burned
Therefore, in t hours, (1.1t) inches of the candle would have burned since the candle was lit
(b) Remaining length of candle = length of candle before it was lit - length of candle that have burned = 16 inches - 1.1t inches = (16 - 1.1t) inches
The rule is -3, then +2
24-3 = 21
21 + 2 = 23
23-3= 20
20+2= 22
22-3= 19
19+2 = 21
21-3= 18
18+2 = 20
