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GrogVix [38]
3 years ago
14

What is the slope of the line that passes through (2, 5) and (−1, 5)?

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0
(2,5)(-1,5)....notice that ur y's are the same number...they are both 5.
This means that u have a horizontal line which has a slope of 0. If the y's are the exact same number, then u have a horizontal line.

if the x's would have been the same number, then u would have had a vertical line with an undefined slope
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Compute the radius of a circle with a circumference of 255 inches. Use 3.14 for pi
gogolik [260]

Answer:

the answer is 40 hope this helps you

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2 years ago
The part that's cut off it says To the nearest tenth of a percent, what's percent... ​
andriy [413]

Answer:

Yes you are correct.

5 0
2 years ago
Ben has collected one more marble than three times the number of marbles as jerry. together they have 229. how many marbles does
Margarita [4]
Working backwards, we first subtract 1. That is 228. Next you divide 228 by 4, which is how many parts they have in all. That is 57. 57 times 3 is how much ben has. Your answer is 171.

8 0
3 years ago
Scientists were studying a rare species of parrot they went to fourth in the year 2010 and found there were 608 pairs in the for
Stells [14]

Answer:

6926 pairs in 2016.

Step-by-step explanation:

The number of pairs in t years after 2010 is modeled by the following function:

P(t) = P(0)(1+r)^{t}

In which P(0) is the number of pairs in 2010 and r is the growth rate, as a decimal.

608 pairs in 2010

This means that P(0) = 608

So

P(t) = P(0)(1+r)^{t}

P(t) = 608(1+r)^{t}

4617 pairs five year later.

So P(5) = 4617. We use this to find 1 + r.

P(t) = 608(1+r)^{t}

4617 = 608(1+r)^{5}

(1+r)^{5} = \frac{4617}{608}

1 +r = \sqrt[5]{\frac{4617}{608}}

1 + r = 1.5

So

P(t) = 608(1.5)^{t}

How many pairs in 2016?

2016 is 2016 - 2010 = 6 years after 2010. So this is P(6).

P(t) = 608(1.5)^{t}

P(6) = 608(1.5)^{6} = 6926

6926 pairs in 2016.

7 0
3 years ago
Which statement regarding the function y=cos(x) is true?
dimaraw [331]
Hints:
use the calculator to check if any of the options are correct.  Try x=pi/6 (or 30 degrees).

Odd functions satisfy the property
f(x)=-f(-x)
For this reason, odd functions are symmetrical about the origin.
Examples of odd functions: sin(x), x^3, x+3x^5, tan(x), sin(x)*cos(x), x*sin(x)
(use your calculator to check that the above are true).

Even functions satisfy the property
f(x)=f(-x)
Even functions are symmetrical about the y-axis.
Examples: x^2, cos(x), x^4+2, |x|, sin^2(x), x^2*cos(x)

There are functions that are neither odd nor even, 
examples:
x^2+4x+3, sin(x)+cos(x)
5 0
3 years ago
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