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3 years ago

8

Help me with this problem !!!!!!!!!!

1 answer:

Mamont248 [21]3 years ago

3 0

Answer:

Hi, your answer is y= $-\frac{1}{2} x$ -3

Step-by-step explanation:

We will use the slope-intercept formula which is

$\frac{y2-y1}{x2-x1}$

We will use two points in this case I'll use

(-2,-2) and (-8,1)

$\frac{1-(-2)}{-8-(-2)}$ = $-\frac{3}{6}$ which can be simplified as $-\frac{1}{2}$

Your Y will be -3

which your final answer will be y=-1/2x-3

Hope this helps :)

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3 years ago

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densk [106]

Answer:

$A.\ y = x^2 - 6x + 13$ is the correct answer.

Step-by-step explanation:

We know that vertex equation of a parabola is given as:

$y = a(x-h)^2+k$

where $(h,k)$ is the vertex of the parabola and

$(x,y)$ are the coordinate of points on parabola.

As per the question statement:

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Let $a = +1$

Minimum of parabola is at x = 3.

The vertex is at the minimum point of a parabola that opens upwards.

$\therefore$ $h = 3$

Putting value of a and h in the equation:

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Please refer to the graph attached.

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