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Rudik [331]
3 years ago
8

How many zeros are in -5x(x-3)(x^2-16)

Mathematics
2 answers:
il63 [147K]3 years ago
7 0
This is a fourth degree polynomial, so by the fundamental theorem of algebra, there are four zeroes, whether they are complex or real.

The expression can be rational factorized into
-5x(x-3)(x+4)(x-4), so all four factors (hence zeroes) are real.

Answer: There are four real zeroes in <span>-5x(x-3)(x^2-16)</span>
soldier1979 [14.2K]3 years ago
3 0
Count the number of times x is used as a factor of this polynomial.  I count 4.  Thus, this expression will have 4 zeros.
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From a point A that is 8.20 m above level ground, the angle of elevation of the top of a building s 31 deg 20 min and the angle
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⇒ 1\text{ minute } =\frac{1}{60}\text{ degree }

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50\text{ minutes }=\frac{50}{60}=\frac{5}{6}\text{ degree}

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