How many zeros are in -5x(x-3)(x^2-16)

2 answers:

7 0

This is a fourth degree polynomial, so by the fundamental theorem of algebra, there are four zeroes, whether they are complex or real.

The expression can be rational factorized into
-5x(x-3)(x+4)(x-4), so all four factors (hence zeroes) are real.

Answer: There are four real zeroes in <span>-5x(x-3)(x^2-16)</span>

soldier1979 [14.2K]3 years ago

3 0

Count the number of times x is used as a factor of this polynomial. I count 4. Thus, this expression will have 4 zeros.

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