What is the equation of the given linear function?

Mathematics

1 answer:

lbvjy [14]2 years ago

5 0

Answer: A

Step-by-step explanation:

To solve this problem, think of a coordinate plane. Look at the first x and y on the table. The x is zero and the y is 8. Now look at the answers. For x to be zero while y has a value would mean that it would have a y-intercept of 8. The only answer that has a y-intercept of that value is A.

To prove that A is the correct problem, try to do slope intercept with it. The slope is 9, so the y increases by 9 and the x increases by 1. 8 + 9 is 17, which is the second y. 0 + 1 is 1, which is the second x. So A must be the correct answer.

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Suppose a NBA basketball player has 5% chance of picking up a foul every minute he plays. What is the probability that he will p

alukav5142 [94]

Answer:

He wont foul out with probability 0.9093

Step-by-step explanation:

The total number of fools he picked is a Binomial ditribution noted by X with parameters p = 0.05 and N = 48. The mean of this random variable is μ = np = 48*0.05 = 2.4 and the variance is σ² = np(1-p) = 2.4*0.95 = 2.28, hence its standard deviation is σ = √2.28 = 1.51.

Note that, if approximate probability is asked, we could just approximate X with a Normal random variable with mean 2.4 and standard deviation 1.51 (this can be done because of the central limit theorem). We will calculate the probability manually. He wont foul out if he picks 0,1,2,3 or 4 fouls, thus

$P(X \leq 4) = P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4) \\= 0.95^{48}+48*0.95^{47}*0.05+{48 \choose 2}*0.95^{46}*0.05^2+\\{48 \choose 3}*0.95^{45}*0.05^3+{48 \choose 4}*0.95^{44}*0.05^4 \\= 0.085+0.215+0.266+0.215+0.127 = 0.9093$