Question

Summarize a strategy that can be used to graph Py+1=Qx

Answer 1

Answer with explanation:

The given equation is

→  Py+1=Qx

→Qx-P y=1-----(1)

The given equation is equation in two variable , which represents a line.

To draw a line you need two distinct points.

Put, x=0, in equation 1

Gives, -Py=1

$y=\frac{-1}{P}$

Put, y=0, in equation 1

Qx=1

$x=\frac{1}{Q}$

So, the two points which we have to join to graph this equation is             $(\frac{1}{Q},0) \text{and} (0,\frac{-1}{P})$.

Answer 2

You would need to get y be itself to make an equation so you would first subtract 1 from both sides--
Py = Qx - 1
Then you would need to divide both sides by P to have y by itself--
y = Qx-1/P