add the following fraction give me the answer in lowest terms and mixed numbers if necessary. 10/12 +1/2 =

If the value of the blur radius is _____, no shadow will appear

vladimir1956 [14]

The value of the Blur radius is zero

Then no shadow will appear.

4 0

3 years ago

What number is a factor of 12,but not a multiple of 3

choli [55]

There are 3 numbers as such.
First lets list all the factors of 12
1,2,3,4,6,12
now lets see which are multiples of 3
3,6 and 12 are multiples of 3
therefore we are left with
1,2 and 4

6 0

3 years ago

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Find the circumference of a circle whose area is 452.16 square meters ( ue 3.1416 as the value of

IrinaVladis [17]

Area of circle, πr² = 452.16

πr² = 452.16

r² = 452.16/π, π ≈ 3.1416

r = √(452.16/π) = √(452.16/3.1416) ≈ 11.997

Circumference = 2πr

C = 2*3.1416*11.997

C ≈ 75.38

Circumference is ≈ 75.38 m.

Hope this helps.

5 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Anettt [7]

Answer:

Choice C: approximately 121 green beans will be 13 centimeters or shorter.

Step-by-step explanation:

What's the probability that a green bean from this sale is shorter than 13 centimeters?

Let the length of a green bean be $X$ centimeters.

$X$ follows a normal distribution with

mean $\mu = 11.2$ and
standard deviation $\sigma = 2.1$ .

In other words,

$X\sim \text{N}(11.2, 2.1^{2})$ ,

and the probability in question is $X \le 13$ .

Z-score table approach:

Find the z-score of this measurement:

$\displaystyle z= \frac{x-\mu}{\sigma} = \frac{13-11.2}{2.1} = 0.857143$ . Closest to 0.86.

Look up the z-score in a table. Keep in mind that entries on a typical z-score table gives the probability of the left tail, which is the chance that $Z$ will be less than or equal to the z-score in question. (In case the question is asking for the probability that $Z$ is greater than the z-score, subtract the value from table from 1.)

$P(X\le 13) = P(Z \le 0.857143) \approx 0.8051$ .

"Technology" Approach

Depending on the manufacturer, the steps generally include:

Locate the cumulative probability function (cdf) for normal distributions.
Enter the lower and upper bound. The lower bound shall be a very negative number such as $-10^{9}$ . For the upper bound, enter $13$
Enter the mean and standard deviation (or variance if required).
Evaluate.

For example, on a Texas Instruments TI-84, evaluating $\text{normalcdf})(-1\text{E}99,\;13,\;11.2,\;2.1 )$ gives $0.804317$ .

As a result,

$P(X\le 13) = 0.804317$ .

Number of green beans that are shorter than 13 centimeters:

Assume that the length of green beans for sale are independent of each other. The probability that each green bean is shorter than 13 centimeters is constant. As a result, the number of green beans out of 150 that are shorter than 13 centimeters follow a binomial distribution.

Number of trials $n$ : 150.
Probability of success $p$ : 0.804317.

Let $Y$ be the number of green beans out of this 150 that are shorter than 13 centimeters. $Y\sim\text{B}(150,0.804317)$ .

The expected value of a binomial random variable is the product of the number of trials and the probability of success on each trial. In other words,

$E(Y) = n\cdot p = 150 \times 0.804317 = 120.648\approx 121$

The expected number of green beans out of this 150 that are shorter than 13 centimeters will thus be approximately 121.

7 0

3 years ago

How can you use estimation to find

KATRIN_1 [288]

Well you can add to find out that 9 x 5 = 45 and 1/2 x 5 = 2 1/2 so the correct answer is 47 1/2 to estimate it just do 9 x 5 = 45 Hope this helps! :D

4 0

4 years ago

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