The hawk’s centripetal acceleration is 2.23 m/s²
The magnitude of the acceleration under new conditions is 2.316 m/s²
radius of the horizontal arc = 10.3 m
the initial constant speed = 4.8 m/s
we know that the centripetal acceleration is given by
= 
= 23.04/10.3
= 2.23 m/s²
It continues to fly but now with some tangential acceleration
= 0.63 m/s²
therefore the net value of acceleration is given by the resultant of the centripetal acceleration and the tangential acceleration
so
= 
= 
= 2.316 m/s²
So the magnitude of net acceleration will become 2.316 m/s².
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The answer is Rh = 135 cm^3 and B = 0.05185 wh/m^2
Explanation:
Resitivity of silicon = 0.1
thickness = 100um
so, I = ma
Required to find out concentration of electron , we know that
Rh = up
By putting in the values,
Rh = 1350 x 0.1
Rh = 135 cm^3
Now consider,
Rh = 1 / Rh.q
= 1 / Rh . q
= 1 / 135 x1.609 x10^-19
= 4.6037 x 10^16 / cm^3
Vh = BIRh / w
B = Vh w/ IRh
B = -70 x10^-6 x 100 x10^-6 / 1x 10^-3 x 135 x 10^-6
B = 0.05185 wh / m^2
1. Frequency 2. measure from trough to trough
Answer:
Explanation:
Given that
32° F corresponds to 0 °C. ---Point 1
212° F corresponds to 100 °C.----Point 2
We know that if two point is given that equation of line can be found as
Lets C in y- direction and F in x- direction,so we can say that
So the linear relationship is
