All categories

3 years ago

What is the perimeter of a square with the side length of 5-3x?

Mathematics

1 answer:

Oliga [24]3 years ago

4 0

Answer:

Step-by-step explanation:

Finding the perimeter means adding all size. so...

each side of a square is 5-3x, so

5-3x + 5-3x + 5-3x + 5-3x = -12x+20

You might be interested in

Solve the equation. |x + 5| = 9 {–4, 14} {–14, 4} {4, 14} {–14, –4}

inna [77]

Answer:

{-14, 4}

Step-by-step explanation:

the absolute value function only makes sure that the result always has a positive sign.

so, (x + 5) must be either +9 or -9 to make the original equation true. the absolute value would turn both into +9.

so,

x + 5 = 9

x = 4

and

x + 5 = -9

x = -14

that gives us the correct set of solutions as indicated above.

6 0

2 years ago

50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle

aalyn [17]

Answer:

$EF=4\sqrt{3}$

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

$A_{\text{rect}}=8(6)=48\text{ cm}^2$

The area of the triangle is 1/4 of this. Therefore:

$\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2$

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

$\displaystyle 12=\frac{1}{2}(DE)(DF)$

Since DE = DF:

$24=DF^2$

Thus:

$DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE$

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

$(DE)^2+(DF)^2=(EF)^2$

Therefore:

$(2\sqrt6)^2+(2\sqrt6)^2=EF^2$

Square:

$24+24=EF^2$

Add:

$EF^2=48$

And finally, we can take the square root of both sides:

$EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}$

6 0

3 years ago

Read 2 more answers

Integral of x sqrt(36+x^2) when x = 6tan theta

vova2212 [387]

$(36+{x}^{2})x=6$
$x = 6$

3 0

2 years ago

Justify why a / b x b / c x c /d x d / e is equal to a /e when B C D and E are not zero

Maru [420]

a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d, and e are not zero

PROVE

a/b * b/c * c/d * d/e

= (a/b *b/c) * (c/d * d/e)

= ab/bc * (c/d * d/e)

= a/c * (c/d * d/e)

= a/c * (cd/de)

= a/c * c/e

= ac/ce

= a/e

Therefore, a/b * b/c * c/d * d/e is equal to a/e provided that b, c, d, and e are not zero

7 0

3 years ago

We have seen how to convert specified odds from a "fair bet" into the gamblerâs belief about the likelihood of an event happenin

Brut [27]

I had the same question on my hw and I picked c \(“-)/

4 0

3 years ago