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sammy [17]
3 years ago
10

What is the measure of

Mathematics
2 answers:
djverab [1.8K]3 years ago
8 0

Answer:

measure of what?

Step-by-step explanation:

Volgvan3 years ago
8 0
You need to tell us the measure, what’s the measure?
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Help please !!!!!!!!
Ugo [173]

Answer:

y = -4

x = 3

Step-by-step explanation:

Let's first explain when x = 0

Find where x = 0 on the graph. We are finding what the y-value would be. Trace down the y-axis along the vertical line x = 0. Where does the line intersect the y-axis when x = 0? The answer would be -4

The y-intercept is -4, and the x-value for this is 0, of course. So the correct answer for when x = 0 would be y = -4.

Next, we are told to find x when y = -2. Find where y = -2. Now, staying at y = -2, go horizontally along the x-axis at y = -2 until you reach the line. Boom! You should have connected up with the line at around x = 3. Therefore, when y = -2, x = 3

8 0
4 years ago
you invest $2,000 in a stock plan and another $2,000 in a savings account the stock plan decreases 7% the first year and gains 1
Dahasolnce [82]
After calculating the stock and savings account total I found out that the difference in earning between them is $104.738.
8 0
3 years ago
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If 7x+3=24, find the value of -5 - 6x.<br><br> a)-23<br> b)-7<br> c)1<br> d)17
OlgaM077 [116]
A. -23

If 7x plus 3 equals 24, X equals 3. -5 minus 6 time X(3) equals -23.
6 0
4 years ago
What is the coefficient of the following term?<br> -X
Anna [14]
The answer is -1 because a coefficient is the number in front of the variable which is -1 because there is an invisible 1 before the x
3 0
3 years ago
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Help me plzzzzzzzzz!!!!!!!!!!!!!!!!!!
Anvisha [2.4K]

Answer: ( 12 , 9 )

Step-by-step explanation:

The formula for finding the coordinate of points when a line is externally divided in a given ratio is given by :

x = \frac{p x_{2}+q x_{1}}{p+q}

y = \frac{p y_{2}+q y_{1}}{p+q}

From the question

x_{1} = 2

x_{2} = ?

x = 4

y_{1} = -1

y_{2} = ?

y = 1

p = 1

q = 4

substituting the values into the formula ,we have

x = \frac{p x_{2}+q x_{1}}{p+q}

4 = \frac{1(x_{2})+4(2) }{1+4}

4 = \frac{x_{2}+8}{5}

x_{2} + 8 = 20

x_{2} = 12

Also

y = \frac{p y_{2}+q y_{1}}{p+q}

1 = \frac{y_{2}+4(-1)}{5}

y_{2} - 4 = 5

y_{2} = 9

Therefore , the end of the stencil is located at point ( 12 , 9 )

5 0
3 years ago
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