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3 years ago

Mr Gardner is making 6 treat bags. He has 185 chocolate-covered raisins to share evenly among the treat bags.

Mathematics

2 answers:

Ilya [14]3 years ago

7 0

A) 30 chocolate covered raisins will be in each bag.

B) 5 chocolate covered raisins will be left over

See the photo attached to see the long division.

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.

Amiraneli [1.4K]3 years ago

6 0

Answer:

✎There will be 30 Chocolate-Covered raisins in each bag.

✎ And 5 Remaining.

Step-by-step explanation:

Take 185 and divide it by 6 and you should get 30 per bag with a remainder of 5 :)

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Answer:

25%

Step-by-step explanation:

Discount = 1600 - 1200 = 400

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Ann increased the quantities of all the ingredients in a recipe by 60%, percent. She used 80 grams , of cheese. How much cheese

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3 years ago

I dont the know the answer to c-d=b for c

Vinvika [58]

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4 years ago

A case of Scout cookies has 10 cartons. A carton has 12 boxes. The amount you earn on a whole case is 10(12x) dollars.

Katen [24]

Simplified expression: 120x dollars

Step-by-step explanation:

Given,

Number of cartons in case of Scout cookies = 10 cartons

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Simplified expression: 120x dollars

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3 years ago

An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random

Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters = 12

Total number of blue highlighters = 6

Total number of green highlighters = 4

Total number of orange highlighters = 3

So, the total number of highlighters = 12 + 6 + 4 + 3 = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1) = $\frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}$ = $\frac{12}{25}$

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1 = 11

Also, the number of blue highlighter = 6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2) =

$\frac{\textrm{Total number of yellow + Blue highlighters}}{\textrm{Total Highlighters}}$ = $\frac{17}{25}$

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

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3 years ago