Answer:
The standard change in free energy for the reaction = - 437.5 kj/mole
Explanation:
The standard change in free energy for the reaction:
4 KClO₃ (s) → 3 KClO₄(s) + KCl(s)
Given that ΔGf(KClO3(s)) = -290.9 kJ/mol;
ΔGf(KClO4(s)) = -300.4 kJ/mol;
ΔGf(KCl(s)) = -409 kJ/mol
According to Hess's law
ΔGr (Free energy change of reaction)= ∑(Product free energy - reactant free energy)
⇒ ΔGr⁰ = {3 x (-300.4) + (-409)} - {3 x (- 290.9)}
= - 901.2 - 409 + 872.7
= - 437.5 kj/mole
Answer:
anyywhere between 20-23 miles
Explanation:
it depends what type of oil field u mean
Answer:
-4
Explanation:
PLz give me brainliest I worked hard thank u
Answer:
M is increased loudness
O is decreased loudness
N is decreased pitch
P is increased pitch
Louder soundwaves ten to have longer and deeper waves visa versa.
Increased pitch tends to have shorter soundwaves. visa versa
Answer:
I think it's 6 moles are produced
