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dybincka [34]
3 years ago
11

ENG

Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
8 0
The sun is my black hole and technically is also the way that urnanus comes in contact with suck m wee wee
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At equilibrium, a 1.0 L reaction vessel contains 2.3 mol of Mg(OH)₂ and 0.170 mol of OH⁻. What is the equilibrium concentration
Andru [333]

The value of X for this chemical reaction is 1.65 x 10⁻⁴

<u>Explanation:</u>

Mg (OH)₂(s) <==> Mg²⁺+(aq) + 2OH₋₁(aq)  

Kc= 1.80x10⁻¹¹

KC = [Mg²⁺][OH-]²

Let us assume

Put X = [Mg²⁺] and  2x = [OH-]

1.80x10-11 = (X) (2X)²

1.80x10-11 = 4X³

X³ = 4.5x10⁻¹²

On simplifying the equation we get,

X = 1.65 x 10⁻⁴

The value of X for this chemical reaction is 1.65 x 10⁻⁴

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Chemical I’m learning that stuff too :)
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3 years ago
What volume of o2 is needed to react fully with 720. Ml of nh3
Galina-37 [17]

Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.

<h3>What is volume?</h3>

Volume is the area occupied by the substance and is the ratio of the mass to the density.

At STP, 1 mole of gas occupies 22.4 L of volume

Given,

Volume of ammonia reacted = 0.720 L

The combustion reaction is shown as,

\rm 4NH_{3} + 5O_{2} \rightarrow 4NO +6H_{2}O

From the stoichiometry of the reaction, it can be said that,

(4 \times  22.4) L of ammonia reacts with (5 \times  22.4) L of oxygen gas.

So, 0.720 L of  ammonia will react with:

\dfrac{ (5 \times  22.4)}{(4 \times  22.4)} \times 0.720 = 0.9 \;\rm L

Therefore, the volume of oxygen required is 900 mL.

Learn more about volume here:

brainly.com/question/14090111

#SPJ4

6 0
2 years ago
If the temperature of an object is 335 K, how would this be expressed on the Celsius scale? A. 62°C B. 273°C C. 37°C D. 608°C
BaLLatris [955]
335k-273.15=61.85c If rounded then the answer is A
3 0
4 years ago
Read 2 more answers
C. 2.86 g
KiRa [710]
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3 years ago
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