When the equation below is balanced, the coefficient of sulfuric acid, h2so4 is: nacn + h2so4 → na2so4 + hcn?

Select the correct answer.

konstantin123 [22]

Answer:

A. not wearing goggles when breaking a rock with a hammer

Explanation:

You could get extremely hurt if you are not wearing goggles while doing lab work.

6 0

3 years ago

When driving a truck,is fuel crucial?

Natali [406]

Answer:

The answer is yes.

Explanation:

When driving any type of motorized vehicle, fuel is importatn. Fuel is what it runs on, so without it it wouldn't run. With trucks a lot more is needed because trucks are bigger, and tend to carry more than a little car does.

6 0

4 years ago

Suppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particles and both particles are ac

Vitek1552 [10]

Answer:

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

Explanation:

DT the best and they I'm on to work use as some help new thread so this communication contains you would appreciate everything about getting started using some new version from here or email the day car rental house has come home today was automatically and your company based website has anyone that a big hugs bhi to

6 0

3 years ago

How many potassium atoms are in 250.0 grams of potassium?

loris [4]

Hi!

The correct option would be 3.85x10^(24)

To find the number of atoms in 250g of potassium, we need to first calculate the number of atoms in

1 mole of Potassium = 39g which contains 6.022x10^(23) atoms of K

<em>(Avogadro's constant value for the amount of molecules/atoms in one mole of any substance)</em>

<em>Solution</em>

So as 39g of Potassium contains 6.022x10^(23) K atoms

1g of Potassium would contain 6.022x10^(23) / 39 = 1.544 x10^(22) atoms

So 250g of Potassium would contain 1.544x10^(22) x 250 = 3.86x10^(24) atoms

3 0

3 years ago

A solution contains 0.140 mol KCl in 2.100 L water. What is the concentration of KCl in g/L?

viva [34]

<h3><u>Answer</u>;</h3>

≈ 4.95 g/L

<h3><u>Explanation;</u></h3>

The molar mass of KCl = 74.5 g/mole

Therefore; 0.140 moles will be equivalent to ;

= 0.140 moles × 74.5 g/mole

= 10.43 g

Concentration in g/L

= mass in g/volume in L

= 10.43/2.1

= 4.9667

4 0

3 years ago