Question

Which of the following is equal to the rational expression when x ≠ -4 or 16?

Answer 1

Answer:

C

Step-by-step explanation:

Given

$\frac{x^2-16}{(x-16)(x+4)}$

The numerator is a difference of squares

x² - 16 = (x - 4)(x + 4)

= $\frac{(x-4)(x+4)}{(x-16)(x+4) }$ ← cancel the common factor (x + 4) on numerator/ denominator

= $\frac{x-4}{x-16}$ → C