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harkovskaia [24]
3 years ago
12

Answer for brainliest

Mathematics
1 answer:
dmitriy555 [2]3 years ago
7 0

Answer:

average rate of change is 3/2

Step-by-step explanation:

Recall that the average rate of change in an interval [x1, x2], is defined as:

[f(x2)-f(x1)] / (x2 - x1)

which for the interval [0, 2] becomes:

[f(2)-f(0)] / (2 - 0)

From the graph we read that f(0)= 1 and f(2) = 4, therefore:

[f(2)-f(0)] / (2 - 0) = [4 - 1] / 2 = 3/2

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jolli1 [7]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Given cos ⁡ ( θ ) = 5/6 , then sin ⁡ ( θ ) = a/b .<br><br> Determine the values of a and b.
slega [8]

Answer:

a = √11 and b = 6

Step-by-step explanation:

Refer to attached picture for reference

for an right triangle with angle θ

we are given

cos θ = 5/6 = length of adjacent side / length of hypotenuse

hence

adjacent length = 5 units

hypotenuse length = 6 units

the missing side is the "opposite" length which we can find with the Pythagorean equation. in our case:

hypotenuse ² = adjacent ² + opposite²   (rearrange)

opposite ² = hypotenuse ² - adjacent ²

opposite ² = 6² - 5²

opposite = √ (6²-5²) = √11

sin θ = opposite length / hypotenuse  (substitute values above)

sin θ = √11 / 6

hence a = √11 and b = 6

3 0
3 years ago
Add (2x + 2) and (4x – 7)
natta225 [31]
The right answer is 6x + 5
4 0
3 years ago
A football team has a probability of .75 of winning when playing any of the other four teams in its conference. If the games are
Alexeev081 [22]

Answer:

0.3164 = 31.64% probability the team wins all its conference games

Step-by-step explanation:

For each conference game, there are only two possible outcomes. Either the team wins it, or they lose. The probability of winning a game is independent of any other game. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A football team has a probability of .75 of winning when playing any of the other four teams in its conference.

The probability means that p = 0.75, and four games means that n = 4

If the games are independent, what is the probability the team wins all its conference games?

This is P(X = 4). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.75)^{4}.(0.25)^{0} = 0.3164

0.3164 = 31.64% probability the team wins all its conference games

4 0
3 years ago
Plz help me if u don’t know plz don’t answer I don’t have many points
Olenka [21]

Answer:1st same  2nd same 3rd diffrent 4 the same

Step-by-step explanation:

6 0
3 years ago
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