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3 years ago

Momentum is a measure of the _ of an object. Answer motion

Physics

2 answers:

Lorico [155]3 years ago

4 0

Hi Mandy!

Question - Momentum is a measure of the _ of an object.

Answer - motion

Why - Momentum is just another word for motion.

Hope this Helps :)

DedPeter [7]3 years ago

4 0

Answer:

Motion

Explanation:

Momentum is defined as the product of mass of an object and it's velocity.

The formula for momentum is given by

p = m v

It is a vector quantity as velocity is a vector quantity.

The measurement of motion of the object is called momentum.

The SI unit of momentum is kg m / s.

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A plane is travelling at 250km/h and must reach a target that is 3h 58min away. The distance to the target is. *

wariber [46]

Answer:

B) 89500 km

Explanation:

speed = distance / time

time= 3h 58 min = 30+58/60= 30.966 h = 31 hrs (approxx)

250= distance / 31

250× 31= distance

distance = 7750 ( approxx)

but none of the given options is 7750 km so we will choose the answer nearest to it,

therefore 89500km is the right answer

5 0

3 years ago

What average net force is required to stop a 3.5 kg bowling ball initially travelling at a speed of 1.5 m/s over a distance of 0

raketka [301]

First the aceleration:

Vf² = Vo² - 2ad

a = (Vf² - Vo²) / 2d

a = (0 m/s)² - (1,5 m/s)²) / 2 * 0,4 m

a = -2,25 m²/s² / 0,8 m

a = -2,81 m/s²

Now, for the net force, use 2nd law of Newton:

F = ma

F = 3,5 kg * (-2,81 m/s²)

F = -9,835 N

The force for stop the bowling ball is <u>-9,835 Newtons.</u>

7 0

3 years ago

A disk rotates about its central axis starting from rest and accelerates with constant angular acceleration. At one time it is r

aivan3 [116]

Answer:

Explanation:

Given that,

Initial angular velocity is 0

ωo=0rad/s

It has angular velocity of 11rev/sec

ωi=11rev/sec

1rev=2πrad

Then, wi=11rev/sec ×2πrad

wi=22πrad/sec

And after 30 revolution

θ=30revolution

θ=30×2πrad

θ=60πrad

Final angular velocity is

ωf=18rev/sec

ωf=18×2πrad/sec

ωf=36πrad/sec

a. Angular acceleration(α)

Then, angular acceleration is given as

wf²=wi²+2αθ

(36π)²=(22π)²+2α×60π

(36π)²-(22π)²=120πα

Then, 120πα = 8014.119

α=8014.119/120π

α=21.26 rad/s²

Let. convert to revolution /sec²

α=21.26/2π

α=3.38rev/sec

b. Time Taken to complete 30revolution

θ=60πrad

∆θ= ½(wf+wi)•t

60π=½(36π+22π)t

60π×2=58πt

Then, t=120π/58π

t=2.07seconds

c. Time to reach 11rev/sec

wf=wo+αt

22π=0+21.26t

22π=21.26t

Then, t=22π/21.26

t=3.251seconds

d. Number of revolution to get to 11rev/s

∆θ= ½(wf+wo)•t

∆θ= ½(0+11)•3.251

∆θ= ½(11)•3.251

∆θ= 17.88rev.

5 0

3 years ago

Read 2 more answers

State the condition under which a satellite would move with escape velocity

elixir [45]

When the launch velocity is a bit less than the escape velocity, the satellite with time will find itself back to earth and when the speed is far beyond the escape velocity, the satellite with time, be lost in space.

The velocity of escape from the less massive Moon is about 2.4 km per second at its surface. ... A planet (or satellite) cannot long retain an atmosphere if the planet's escape velocity is low enough to be near the average velocity of the gas molecules making up the atmosphere.

7 0

3 years ago

A jet plane is flying at a constant altitude. At time t1 = 0, it has components of velocity vx = 90 m/s, vy = 110 m/s. At time t

Vika [28.1K]

Answer:

a) See attachment.

b) a_avg = -8.66 i - 2.33 j

c) a = 195 degrees from + x-axis. |a_avg| = 8.97 m/s^2

Explanation:

Given:

- Initial Velocity V_i = (90 i + 110 j)

- Final velocity V_f = (-170 i + 40 j)

- t_i = 0

- t_f = 30.0 s

Find:

(a) Sketch the velocity vectors at t1 and t2. How do these two vectors differ?

(b) the components of the average acceleration

Solution:

- The change in velocity is given by:

Δ V = (V_f - V_i)

Δ V = ( -170 i - 90 i + 40 j - 110 j)

Δ V = (-260 i - 70 j)

- The change in time is given as:

Δ t = t_f - t_i = 30 - 0 = 30 s

-The average acceleration is:

a_avg = Δ V / Δ t

a_avg = (-260 i - 70 j) / 30

a_avg = -8.66 i - 2.33 j

- The magnitude of acceleration is:

|a_avg| = sqrt ( 8.66^2 + 2.33^2)

|a_avg| = sqrt (80.4245)

|a_avg| = 8.97 m/s^2

- The direction of acceleration is given by:

tan (Q) = a_y / a_x

Q = arctan(a_y / a_x)

Q = arctan(2.33 / 8.66)

Q = 15 degrees

Hence, 180 + 15 = a. a = 195 degrees from + x-axis.

8 0

3 years ago