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daser333 [38]
3 years ago
11

What average net force is required to stop a 3.5 kg bowling ball initially travelling at a speed of 1.5 m/s over a distance of 0

.4 m?
Physics
1 answer:
raketka [301]3 years ago
7 0

First the aceleration:

Vf² = Vo² - 2ad

a = (Vf² - Vo²) / 2d

a = (0 m/s)² - (1,5 m/s)²) / 2 * 0,4 m

a = -2,25 m²/s² / 0,8 m

a = -2,81 m/s²

Now, for the net force, use 2nd law of Newton:

F = ma

F = 3,5 kg * (-2,81 m/s²)

F = -9,835 N

The force for stop the bowling ball is <u>-9,835 Newtons.</u>

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A mosquito and a truck have a head-on collision. Which has a larger change of momentum?
Maksim231197 [3]

Answer:

C. They have the same change of momentum.

Explanation:

Let "m" be the mass and "v" the velocity.

According to the property of conservation of momentum, when objects 1 and 2 collide:

m_{a}v_{ai} + m_{b}v_{bi} = m_{a}v_{afinal} + m_{b}v_{bfinal}\\m_{b}v_{bfinal} - m_{b}v_{bi} = m_{a}v_{ai} - m_{a}v_{afinal}\\\Delta (m_{b}v_{b}) = -\Delta (m_{a}v_{a})

Therefore, one can conclude that the change in momentum (Δ(mv)) has the same magnitude but opposite sign for any two objects regardless of how much heavier one might be than the other.

They have the same change of momentum.

8 0
3 years ago
A cyclist is riding a bicycle at a speed of 22 mph on a horizontal road. The distance between the axles is 42 in., and the mass
stealth61 [152]

Answer:

The shortest distance is  S = 24.86 ft

Explanation:

The free body diagram of this question is shown on the first uploaded image

From the question we are told that

   The speed of the bicycle is v_b = 22\ mph = 22 * \frac{5280}{3600}   =  32.26 ft/s

     The distance between the axial is  d = 42 \ in

The mass center of the cyclist and the bicycle is m_c = 26 \ in  behind the front axle

The mass center of the cyclist and the bicycle is m_h = 40 \ in above the ground

   For the bicycle not to be thrown over the

     Momentum about the back wheel must be zero so

                \sum _B = 0

=>             mg (26) = ma(40)

=>             a = \frac{26}{40} g

Here  g = 32.2 ft/s^2

     So     a =  \frac{26}{40} (32.2)

             a =  20.93 ft/s^2

Apply the equation of motion to this motion we have

       v^2 = u^2 + 2as

 Where  u = 32.26 ft /s

             and v = 0 since the bicycle is coming to a stop

        v^2 = (32.26)^2 - 2(20.93) S

=>      S = 24.86 ft        

                 

5 0
3 years ago
which machine changes the direction of force needed to do a task without changing the size of the force needed?
Evgen [1.6K]
<span>A pulley is able to do that.</span>
7 0
4 years ago
A jogger runs 5.0 km on a straight trail at an angle of 60° south of west. What is the southern component of the run rounded to
geniusboy [140]

Answer:

4.3 km

Explanation:

5 0
2 years ago
What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?
dezoksy [38]

Answer:

the f is 1.3 m

Explanation:

Given that

An object 2.0m is from the concave mirror

And, the image is 4.0m from the mirror

We need to find out the f

So,

u = -2 m

v = -4 m

1 ÷ f = 1 ÷ v + 1 ÷ u

= (-1 ÷ 4) + (-1 ÷ 2)

= -3 ÷4

f = -4 ÷ 3

= |1.3| m

Hence, the f is 1.3 m

7 0
3 years ago
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